如何在 Swift 3 中发送消息和链接到 WhatsApp？

Question

如何在 Swift 3 中发送消息和链接到 WhatsApp

我正在使用此代码： Code

向控制台发送错误消息：

... URL 失败：“whatsapp://send?text=Check” - 错误：“此应用是 不允许查询方案whatsapp”

谢谢

Answer 1

斯威夫特 5

请按照以下步骤通过 URL Schemes 在 WhatsApp 上分享

1. 将此代码添加到您的应用“info.plist”中

<key>LSApplicationQueriesSchemes</key>
<array>
  <string>whatsapp</string>
</array>

1. 用于分享文字和网址

    @IBAction func whatsappShareText(_ sender: AnyObject) {
    let message = "First Whatsapp Share & https://www.google.co.in"
    var queryCharSet = NSCharacterSet.urlQueryAllowed
   
    // if your text message contains special char like **+ and &** then add this line
    queryCharSet.remove(charactersIn: "+&")
   
    if let escapedString = message.addingPercentEncoding(withAllowedCharacters: queryCharSet) {
        if let whatsappURL = URL(string: "whatsapp://send?text=\(escapedString)") {
            if UIApplication.shared.canOpenURL(whatsappURL) {
                UIApplication.shared.open(whatsappURL, options: [: ], completionHandler: nil)
            } else {
                debugPrint("please install WhatsApp")
            }
        }
    }
   

   }

编码愉快！

Answer 2

你应该试试这个：

注意：您的设备中必须安装 whatsapp 应用程序。

斯威夫特 3

var documentInteractionController: UIDocumentInteractionController = UIDocumentInteractionController()

@IBAction func whatsappShareText(_ sender: AnyObject)
{
    let originalString = "First Whatsapp Share"
    let escapedString = originalString.addingPercentEncoding(withAllowedCharacters:CharacterSet.urlQueryAllowed)

    let url  = URL(string: "whatsapp://send?text=\(escapedString!)")

    if UIApplication.shared.canOpenURL(url! as URL)
    {
        UIApplication.shared.open(url! as URL, options: [:], completionHandler: nil)
    }
}

@IBAction func whatsappShareLink(_ sender: AnyObject)
{
    let originalString = "https://www.google.co.in"
    let escapedString = originalString.addingPercentEncoding(withAllowedCharacters:CharacterSet.urlQueryAllowed)
    let url  = URL(string: "whatsapp://send?text=\(escapedString!)")

    if UIApplication.shared.canOpenURL(url! as URL)
    {
        UIApplication.shared.open(url! as URL, options: [:], completionHandler: nil)
    }
}

将此代码添加到您的应用“info.plist”中

<key>LSApplicationQueriesSchemes</key>
<array>
    <string>whatsapp</string>
</array>