【发布时间】:2014-03-14 09:35:05
【问题描述】:
我创建了 2 个函数: - 一个记录麦克风 - 一种播放麦克风声音的工具
它会记录麦克风 3 秒
#include <iostream>
#include <Windows.h>
#include <vector>
using namespace std;
#pragma comment(lib, "winmm.lib")
short int waveIn[44100 * 3];
void PlayRecord();
void StartRecord()
{
const int NUMPTS = 44100 * 3; // 3 seconds
int sampleRate = 44100;
// 'short int' is a 16-bit type; I request 16-bit samples below
// for 8-bit capture, you'd use 'unsigned char' or 'BYTE' 8-bit types
HWAVEIN hWaveIn;
MMRESULT result;
WAVEFORMATEX pFormat;
pFormat.wFormatTag=WAVE_FORMAT_PCM; // simple, uncompressed format
pFormat.nChannels=1; // 1=mono, 2=stereo
pFormat.nSamplesPerSec=sampleRate; // 44100
pFormat.nAvgBytesPerSec=sampleRate*2; // = nSamplesPerSec * n.Channels * wBitsPerSample/8
pFormat.nBlockAlign=2; // = n.Channels * wBitsPerSample/8
pFormat.wBitsPerSample=16; // 16 for high quality, 8 for telephone-grade
pFormat.cbSize=0;
// Specify recording parameters
result = waveInOpen(&hWaveIn, WAVE_MAPPER,&pFormat,
0L, 0L, WAVE_FORMAT_DIRECT);
WAVEHDR WaveInHdr;
// Set up and prepare header for input
WaveInHdr.lpData = (LPSTR)waveIn;
WaveInHdr.dwBufferLength = NUMPTS*2;
WaveInHdr.dwBytesRecorded=0;
WaveInHdr.dwUser = 0L;
WaveInHdr.dwFlags = 0L;
WaveInHdr.dwLoops = 0L;
waveInPrepareHeader(hWaveIn, &WaveInHdr, sizeof(WAVEHDR));
// Insert a wave input buffer
result = waveInAddBuffer(hWaveIn, &WaveInHdr, sizeof(WAVEHDR));
// Commence sampling input
result = waveInStart(hWaveIn);
cout << "recording..." << endl;
Sleep(3 * 1000);
// Wait until finished recording
waveInClose(hWaveIn);
PlayRecord();
}
void PlayRecord()
{
const int NUMPTS = 44100 * 3; // 3 seconds
int sampleRate = 44100;
// 'short int' is a 16-bit type; I request 16-bit samples below
// for 8-bit capture, you'd use 'unsigned char' or 'BYTE' 8-bit types
HWAVEIN hWaveIn;
WAVEFORMATEX pFormat;
pFormat.wFormatTag=WAVE_FORMAT_PCM; // simple, uncompressed format
pFormat.nChannels=1; // 1=mono, 2=stereo
pFormat.nSamplesPerSec=sampleRate; // 44100
pFormat.nAvgBytesPerSec=sampleRate*2; // = nSamplesPerSec * n.Channels * wBitsPerSample/8
pFormat.nBlockAlign=2; // = n.Channels * wBitsPerSample/8
pFormat.wBitsPerSample=16; // 16 for high quality, 8 for telephone-grade
pFormat.cbSize=0;
// Specify recording parameters
waveInOpen(&hWaveIn, WAVE_MAPPER,&pFormat, 0L, 0L, WAVE_FORMAT_DIRECT);
WAVEHDR WaveInHdr;
// Set up and prepare header for input
WaveInHdr.lpData = (LPSTR)waveIn;
WaveInHdr.dwBufferLength = NUMPTS*2;
WaveInHdr.dwBytesRecorded=0;
WaveInHdr.dwUser = 0L;
WaveInHdr.dwFlags = 0L;
WaveInHdr.dwLoops = 0L;
waveInPrepareHeader(hWaveIn, &WaveInHdr, sizeof(WAVEHDR));
HWAVEOUT hWaveOut;
cout << "playing..." << endl;
waveOutOpen(&hWaveOut, WAVE_MAPPER, &pFormat, 0, 0, WAVE_FORMAT_DIRECT);
waveOutWrite(hWaveOut, &WaveInHdr, sizeof(WaveInHdr)); // Playing the data
Sleep(3 * 1000); //Sleep for as long as there was recorded
waveInClose(hWaveIn);
waveOutClose(hWaveOut);
}
int main()
{
StartRecord();
return 0;
}
我怎样才能改变我的 StartRecord 功能(我猜我的 PlayRecord 功能也是如此),让它一直录制到麦克风没有输入为止?
(到目前为止,这两个功能运行良好 - 将麦克风录制 3 秒,然后播放录音)...
谢谢!
编辑:没有声音,我的意思是音量太低或其他什么(意味着这个人可能没有说话)......
【问题讨论】:
-
没有“没有声音”这回事。相反,声级会在一段时间内降至某个阈值以下。
-
这就是我的意思。那么如何检查音量呢?
-
@KenWhite 这不是,因为在这个线程中,我试图将 1 个函数拆分为 2 个,而在这里我试图改变它......
-
“开始录制,我对着麦克风说一个词,当沉默一两秒时它会停止录制还是什么?”不等于“在没有麦克风输入之前让它录音?”
标签: c++ winapi voip voice-recording