为什么数据没有保存在数组中？ |不和谐.js v13

Question

每当我尝试将数据推送到数组中时，然后在 for 循环之后记录它，它只会打印一个空数组。这是为什么呢？

const discord = require('discord.js');
const db = require('quick.db');
const fs = require('fs');

module.exports = {
    name: 'XYZ',
    run: async (client, message) => {

        var array_V = ['ID1', 'ID2'];
        var snowflakes = [];
        var i = 0;

        message.guild.channels.cache.forEach(channel => {
            if (!channel.isText()) return;
            for (const channel of message.guild.channels.cache.values()) {
                let messages = await channel.messages.fetch()
                messages.each((msg) => {
                  if (msg.author.id === array_V[i]) {
                    snowflakes.push(msg.createdTimestamp)
                  }
                })
            }
        });
    }      
}   

现在输出SyntaxError: await is only valid in async functions and the top level bodies of modules，尽管它已经在标头中声明为异步函数。

Answer 1

您将其推送到.then。使用await 和for 循环来更新它并然后运行下一个代码

for (const channel of message.guild.channels.cache.filter(c => c.type === "GUILD_TEXT").values()) {
  let messages = await channel.messages.fetch()
  messages.each((msg) => {
    if (msg.author.id === array_V[i]) {
      snowflakes.push(msg.createdTimestamp)
    }
  })
}

这应该可以工作，因为所有异步都在 for 循环中等待