通过电话、电子邮件、姓名在 AddressBook 中查找 ios ABRecordRef 联系人

Question

我需要在 AdreesBook 中找到一个联系人才能添加一个新的社交网络。 有时我必须通过电话和电子邮件或电话（名字和姓氏）查找联系人，是否有任何查询来获取 ABRecordRef 联系人而不是做 while？

我的许多用户有超过 1000 个联系人，我需要更新其中的许多人，所以如果我唯一的解决方案是做这么多时间，那效率不高...

有什么想法吗？？

谢谢！

Answer 1

以下方法可以帮助您使用电话号码获取联系方式。为此它使用了kABPersonPhoneProperty，同样你可以编写另一个函数来搜索email和name：

• 对于 email，使用属性：kABPersonEmailProperty
• 对于名字：kABPersonFirstNameProperty

更多详情，请转至：ABPerson Reference

希望这会有所帮助。

#import <AddressBook/AddressBook.h>

-(NSArray *)contactsContainingPhoneNumber:(NSString *)phoneNumber {
    /*
     Returns an array of contacts that contain the phone number
     */

    // Remove non numeric characters from the phone number
    phoneNumber = [[phoneNumber componentsSeparatedByCharactersInSet:[[NSCharacterSet alphanumericCharacterSet] invertedSet]] componentsJoinedByString:@""];

    // Create a new address book object with data from the Address Book database
    CFErrorRef error = nil;
    ABAddressBookRef addressBook = ABAddressBookCreateWithOptions(NULL, &error);
    if (!addressBook) {
        return [NSArray array];
    } else if (error) {
        CFRelease(addressBook);
        return [NSArray array];
    }

    // Requests access to address book data from the user
    ABAddressBookRequestAccessWithCompletion(addressBook, ^(bool granted, CFErrorRef error) {});

    // Build a predicate that searches for contacts that contain the phone number
    NSPredicate *predicate = [NSPredicate predicateWithBlock: ^(id record, NSDictionary *bindings) {
        ABMultiValueRef phoneNumbers = ABRecordCopyValue( (__bridge ABRecordRef)record, kABPersonPhoneProperty);
        BOOL result = NO;
        for (CFIndex i = 0; i < ABMultiValueGetCount(phoneNumbers); i++) {
            NSString *contactPhoneNumber = (__bridge_transfer NSString *) ABMultiValueCopyValueAtIndex(phoneNumbers, i);
            contactPhoneNumber = [[contactPhoneNumber componentsSeparatedByCharactersInSet:[[NSCharacterSet alphanumericCharacterSet] invertedSet]] componentsJoinedByString:@""];
            if ([contactPhoneNumber rangeOfString:phoneNumber].location != NSNotFound) {
                result = YES;
                break;
            }
        }
        CFRelease(phoneNumbers);
        return result;
    }];

    // Search the users contacts for contacts that contain the phone number
    NSArray *allPeople = (NSArray *)CFBridgingRelease(ABAddressBookCopyArrayOfAllPeople(addressBook));
    NSArray *filteredContacts = [allPeople filteredArrayUsingPredicate:predicate];
    CFRelease(addressBook);

    return filteredContacts;
}