计数不和谐机器人python

Question

我查看了其他代码并没有弄清楚，我想要的是每当发送数字时都会发送消息，每次发送所述数字时，数字都会增加一。这是我的代码：

 counter = 0

if message.channel.startswith(counter):
    await message.channel.send(‘test, this will be changed later’)
    counter +=1```

Answer 1

您可能需要先转换为字符串......

counter = 0

if message.channel.startswith(str(counter)):
    await message.channel.send("test, this will be changed later")
    counter += 1

Answer 2

这会给频道带来什么？

counter = 0

await channel.send(f'Start waiting for counter: {counter}')

if message.channel.startswith(str(counter)):
    counter += 1
    await channel.send(f'waiting for new counter: {counter}')

Answer 3

好的，现在我知道你的问题是什么了。您正在使用 discord.py 并且每次编写消息时都会触发事件 onMessage ，因此您每次创建一个名为“counter”的新变量，其值为 0，然后将其增加到 1，但 counter int 永远不会保存。对此的修复是某种数据源。您可以尝试每次保存号码，例如在一个 txt 文件中。这应该使它工作（代码）：

counter = 0

# What the Message should start with
if message.content.startswith('Text'):
    # Try to read the file, if it is not existing create it with 0 as number in it.
    try:
        f = open("counter.txt", "r")
        # Set the content of the text file as counter int
        counter = int(f.readline())
    except:
        f = open("counter.txt", "a")
        f.write(str(0))

    # Add a Number to the Counter
    counter += 1
    # Overwrite the current Number with the New Number
    f = open("counter.txt", "w")
    f.write(str(counter))

    # Send a Message with a certain String (Test! in this case and the Int 
    # that got counted up)
    await message.channel.send('Test! ' + str(counter))

Answer 4

+= 在 Python 中不起作用，请改用“var = var + 1”