MySQL - 不和谐 - 发布表/结果

Question

我有一个只提取 1 个结果的代码，我需要它来提取所有结果（或将其限制为 10 个）。有人可以帮助我或指出正确的方向吗？

con.query(`SELECT * FROM events WHERE closed = 'No'`, (err, rows) => {
     if (err) throw err;

     let sql;
     let eventID = rows[0].eventnumber;
     let hostID = rows[0].host;
     let description = rows[0].eventname;
     let participants = rows[0].participants

     const event = `Event ${eventID}: ${description} - Hosted by: <@` + hostID + `>. Participants: ${participants}`

     const listEmbed = new Discord.MessageEmbed()
         .setColor('#ff6600')
         .setTitle('Events')
         .setDescription(`${event}`)


     message.channel.send(listEmbed);

     con.query(sql);
 });

来自数据库的信息如下：

eventnumber	host	eventname	closed	participants
16	123456789012345678	test raid	Yes	test0 test1
17	123456789012345678	test raid	No	test2 test3 test4
18	123456789012345678	test raid	No	test5 test6 test7
19	123456789012345678	test raid	Yes	test0 test1
20	123456789012345678	test raid	No	test2 test3 test4
21	123456789012345678	test raid	No	test5 test6 test7
22	123456789012345678	test raid	Yes	test0 test1
23	123456789012345678	test raid	No	test2 test3 test4
24	123456789012345678	test raid	No	test5 test6 test7
25	123456789012345678	test raid	Yes	test0 test1
26	123456789012345678	test raid	No	test2 test3 test4
27	123456789012345678	test raid	No	test5 test6 test7

编辑：

所以我找到了一种让它显示 10 个事件的方法，但它看起来很难看，我知道有更好的方法似乎无法解决。另外，如果没有 10 个结果满足条件，代码就会出错。

    con.query(`SELECT * FROM events WHERE closed = 'No'`, (err, rows) => {
        if (err) throw err;

        let sql;
        let firstID = rows[0].eventnumber;
        let firstHost = rows[0].host;
        let firstDescription = rows[0].eventname;
        let firstParticipants = rows[0].participants;
        let secondID = rows[1].eventnumber;
        let secondHost = rows[1].host;
        let secondDescription = rows[1].eventname;
        let secondParticipants = rows[1].participants;
        let thirdID = rows[2].eventnumber;
        let thirdHost = rows[2].host;
        let thirdDescription = rows[2].eventname;
        let thirdParticipants = rows[2].participants;
        let fourthID = rows[3].eventnumber;
        let fourthHost = rows[3].host;
        let fourthDescription = rows[3].eventname;
        let fourthParticipants = rows[3].participants;
        let fifthID = rows[4].eventnumber;
        let fifthHost = rows[4].host;
        let fifthDescription = rows[4].eventname;
        let fifthParticipants = rows[4].participants;
        let sixthID = rows[5].eventnumber;
        let sixthHost = rows[5].host;
        let sixthDescription = rows[5].eventname;
        let sixthParticipants = rows[5].participants;
        let seventhID = rows[6].eventnumber;
        let seventhHost = rows[6].host;
        let seventhDescription = rows[6].eventname;
        let seventhParticipants = rows[6].participants;
        let eigthID = rows[7].eventnumber;
        let eigthHost = rows[7].host;
        let eigthDescription = rows[7].eventname;
        let eigthParticipants = rows[7].participants;
        let ninethID = rows[8].eventnumber;
        let ninethHost = rows[8].host;
        let ninethDescription = rows[8].eventname;
        let ninethParticipants = rows[8].participants;
        let tenthID = rows[9].eventnumber;
        let tenthHost = rows[9].host;
        let tenthDescription = rows[9].eventname;
        let tenthParticipants = rows[9].participants;

        const firstEvent = `**Event ${firstID}:** ${firstDescription}\n**Hosted by:** <@` + firstHost + `>\n**Participants:** ${firstParticipants}`
        const secondEvent = `**Event ${secondID}:** ${secondDescription}\n**Hosted by:** <@` + secondHost + `>\n**Participants:** ${secondParticipants}`
        const thirdEvent = `**Event ${thirdID}:** ${thirdDescription}\n**Hosted by:** <@` + thirdHost + `>\n**Participants:** ${thirdParticipants}`
        const fourthEvent = `**Event ${fourthID}:** ${fourthDescription}\n**Hosted by:** <@` + fourthHost + `>\n**Participants:** ${fourthParticipants}`
        const fifthEvent = `**Event ${fifthID}:** ${fifthDescription}\n**Hosted by:** <@` + fifthHost + `>\n**Participants:** ${fifthParticipants}`
        const sixthEvent = `**Event ${sixthID}:** ${sixthDescription}\n**Hosted by:** <@` + sixthHost + `>\n**Participants:** ${sixthParticipants}`
        const seventhEvent = `**Event ${seventhID}:** ${seventhDescription}\n**Hosted by:** <@` + seventhHost + `>\n**Participants:** ${seventhParticipants}`
        const eigthEvent = `**Event ${eigthID}:** ${eigthDescription}\n**Hosted by:** <@` + eigthHost + `>\n**Participants:** ${eigthParticipants}`
        const ninethEvent = `**Event ${ninethID}:** ${ninethDescription}\n**Hosted by:** <@` + ninethHost + `>\n**Participants:** ${ninethParticipants}`
        const tenthEvent = `**Event ${tenthID}:** ${tenthDescription}\n**Hosted by:** <@` + tenthHost + `>\n**Participants:** ${tenthParticipants}`

        const listEmbed = new Discord.MessageEmbed()
            .setColor('#ff6600')
            .setTitle('Events')
            .setDescription(`${firstEvent}\n\n${secondEvent}\n\n${thirdEvent}\n\n${fourthEvent}\n\n${fifthEvent}\n\n${sixthEvent}\n\n${seventhEvent}\n\n${eigthEvent}\n\n${ninethEvent}\n\n${tenthEvent}`)


        message.channel.send(listEmbed);

        con.query(sql);
    });

非常感谢您的帮助。

谢谢。

Answer 1

需要添加一个 .forEach 以便它为每个事件发布一次。可能需要防洪。

con.query(`SELECT * FROM events WHERE closed = 'No'`, (err, rows) => {
        if (err) throw err;

        rows.forEach(row => {
            const eventID = row.eventnumber;
            const eventHost = row.host;
            const eventDescription = row.eventname;
            const eventParticipants = row.participants

            const event = `**Event ${eventID}:** ${eventDescription}\n**Hosted by:** <@` + eventHost + `>\n**Participants:** ${eventParticipants}`

            const listEmbed = new Discord.MessageEmbed()
                .setColor('#ff6600')
                .setTitle('Events')
                .setDescription(`${event}`)

            message.channel.send(listEmbed);
        });
    });