机器人代码错误：预期缩进块[重复]答案

【问题标题】：Bot code error: expected an indented block [duplicate]机器人代码错误：预期缩进块[重复]
【发布时间】：2018-03-20 22:44:50
【问题描述】：

所以我目前有这段代码，它为我的不和谐机器人制作了一个 8ball，我遇到了这个错误，上面写着“缩进错误：预期和缩进块”

这是我正在使用的代码（请参阅https://hastebin.com/isageyoqih.py）

import discord
import asyncio
import random
import pickle
import os

client = discord.Client()

@client.event
async def on_ready():
    print('Ready and with')
    print(client.user.name)

@client.event
async def on_message(message):
    if message.content.startswith('_whatcanyoudo?'):
        msg = await client.send_message(message.channel, '```Heres what i can do :```')
        await asyncio.sleep(0.5)
        msg2 = await client.send_message(message.channel, '```For now, i can only do a thing called "flip a coin"```')
        await asyncio.sleep(0.5)
        msg3 = await client.send_message(message.channel, '```Bot powered by Ouindoze™, message will delete in 15 seconds```')
        await asyncio.sleep(15)
        await client.delete_message(msg)
        await client.delete_message(msg2)
        await client.delete_message(msg3)


    elif message.content.startswith('_8ball'):
    8ball = random.choice(['It is certain','As i see it, yes', 'Dont count on it', 'Without a doubt', 'Definitely', 'Very doubtful', 'Outlook not so good', 'My sources say no', 'My reply is no', 'Most likely', 'You may rely on it', 'Ask again later'])
    msg5 = await client.send_message(message.channel, 8ball)

client.run('I obiously won't share the token duh xd')

Here is the error I got.

【问题讨论】：

标签： python discord discord.py

【解决方案1】：

elif message.content.startswith('_8ball'):
8ball = random.choice(['It is certain','As i see it, yes', 'Dont count on it', 'Without a doubt', 'Definitely', 'Very doubtful', 'Outlook not so good', 'My sources say no', 'My reply is no', 'Most likely', 'You may rely on it', 'Ask again later'])
msg5 = await client.send_message(message.channel, 8ball)

应该是（注意elif之后的缩进）

elif message.content.startswith('_8ball'):
    8ball = random.choice(['It is certain','As i see it, yes', 'Dont count on it', 'Without a doubt', 'Definitely', 'Very doubtful', 'Outlook not so good', 'My sources say no', 'My reply is no', 'Most likely', 'You may rely on it', 'Ask again later'])
    msg5 = await client.send_message(message.channel, 8ball)

顺便说一句，8ball 是非法变量名，因为变量名必须以字母或 下划线符号 开头 (_ )。

注意：长列表可以分成多行以提高可读性：

    ball = random.choice([
        'It is certain',
        'As i see it, yes', 
        'Dont count on it', 
        'Without a doubt', 
        'Definitely', 
        'Very doubtful', 
        'Outlook not so good', 
        'My sources say no', 
        'My reply is no', 
        'Most likely', 
        'You may rely on it', 
        'Ask again later'
        ])

【讨论】：

像这样的问题应该被评论并投票关闭作为一个简单的印刷错误。因为这个问题对除了 OP 之外的未来读者没有任何帮助
非常感谢，我已经用了 2 个小时了 xD

【解决方案2】：

elif message.content.startswith('_8ball'):
    8ball = random.choice(['It is certain','As i see it, yes', 'Dont count on it', 'Without a doubt', 'Definitely', 'Very doubtful', 'Outlook not so good', 'My sources say no', 'My reply is no', 'Most likely', 'You may rely on it', 'Ask again later'])
    msg5 = await client.send_message(message.channel, 8ball)

这正是错误消息所说的：缩进它。

【讨论】：