从表 1 插入表 2，其中表 1 上的值输入的时间差大于 5 分钟

Question

编辑：我可能应该说我试图输入信标数据，其中同一信标的下一个数据输入大于 5 分钟

我有问题将表 1 中的值插入到表 2 中，其中信标匹配的表 1 上的数据输入之间存在较大的时间输入差异。

例如ID 7 和 ID 8 之间的数据输入间隙大于 5 分钟，但下面使用的查询我没有返回任何数据

INSERT INTO table
(`beacon`, `zone`, `mac`, `date`, `time`, `id`)

VALUES
("8","GREEN","EE6A6AF29B8E","2018-11-13","16:21:33","1"),
("8","GREEN","EE6A6AF29B8E","2018-11-13","16:21:43","2"),
("8","GREEN","EE6A6AF29B8E","2018-11-13","16:21:53","3"),
("8","GREEN","EE6A6AF29B8E","2018-11-13","16:22:03","4"),
("8","GREEN","EE6A6AF29B8E","2018-11-13","16:22:13","5"),
("8","GREEN","EE6A6AF29B8E","2018-11-13","16:22:32","6"),
("8","GREEN","EE6A6AF29B8E","2018-11-13","16:22:33","7"),
("8","GREEN","EE6A6AF29B8E","2018-11-13","16:30:00","8"),
("8","GREEN","EE6A6AF29B8E","2018-11-13","16:30:33","9"),
("8","GREEN","EE6A6AF29B8E","2018-11-13","16:30:35","10");

返回任何结果的查询我不确定我是否遗漏了一点或只是写错了

select a.beacon, a.zone, a.mac, a.date from table a
join table b
on b.id = (select min(id) from table where id > a.id)
where TIME_TO_SEC(TIMEDIFF(a.time, b.time)) > 300;

我试图将数据从 1 个 mysql 插入到另一个表中，其中表 1 上的数据输入和信标匹配的数据输入到 database.table1 之间的时间大于 5 分钟

例如

"8","GREEN","EE6A6AF29B8E","2018-11-13","16:21:33","1"),
"8","GREEN","EE6A6AF29B8E","2018-11-13","16:22:33","1"),
"8","GREEN","EE6A6AF29B8E","2018-11-13","16:23:33","1"), (Ref 1)
value 8 stopped being inputted into database
"10","GREEN","EE6A6AF29B8E","2018-11-13","16:21:33","1"), 
"10","GREEN","EE6A6AF29B8E","2018-11-13","16:22:33","1"),
"10","GREEN","EE6A6AF29B8E","2018-11-13","16:25:33","1"),
value 8 started inputting into database
"8","GREEN","EE6A6AF29B8E","2018-11-13","16:28:33","1"), (Ref 2)
"8","GREEN","EE6A6AF29B8E","2018-11-13","16:28:33","1"),

REF 1 和 REF 2 之间的差异是 5 分钟，因此将值 8 插入数据库

仅比较信标相同的数据（信标为第一列）

因此，即使在参考 2 之前不到 5 分钟有数据输入，因为信标与参考 2 不同，它也不会考虑此字符串。

Answer 1

你能把你的查询模仿成这个并检查一下吗？

select a.beacon, a.zone, a.mac, a.date from table a
join table b on b.id<a.id
and TIME_TO_SEC(TIMEDIFF(a.time, b.time)) >300; 

基本上你需要那些小于表a的行和满足条件的行。