如何拒绝@everyone 并允许作者查看频道？答案

【问题标题】：How can I deny @everyone and allow the author to view the channel?如何拒绝@everyone 并允许作者查看频道？
【发布时间】：2022-01-05 02:20:26
【问题描述】：

我已经对此进行了一段时间的修改，但我从未创建过基于权限的频道。我正在为我的机器人开发票证功能，但我似乎无法让它工作。这个想法是创建一个具有设置权限的频道，名为 message.author 整个标签，权限设置为只允许 message.author 看到频道。出于某种原因，我一直遇到错误。我怎样才能解决这个问题？我已经定义了所有人角色，并且应该已经定义了 message.author。我错过了什么吗？

if (message.channel.type !== "text") {
  let active = db.fetch(`support_${message.author.id}`)
  let guild = client.guilds.cache.get('took out ID')
  let channel, found = true

  try {
    if (active) client.channels.cache.get(active.channelID).guild
  } catch (e) {
    found = false;
  }

  if(!active || !found) {
    active = {}

    let everyoneRole = msg.guild.roles.cache.find(r => r.name === '@everyone');

    channel = await guild.channels.create(`${message.author.username}-${message.author.discriminator}`, {
      parent: 'took out ID',
      topic: `Support for ${message.author.tag} | ID: ${message.author.id}`,
      permissionOverwrites: [
        {
          id: everyoneRole.id,
          deny: ['VIEW_CHANNEL'],
          
          id: message.author.id,
          allow: ['VIEW_CHANNEL'],
        },
      ],
  })

【问题讨论】：

标签： javascript discord discord.js bots

【解决方案1】：

let everyoneRole = message.guild.id;

@everyone的角色与公会ID相同。

【讨论】：

【解决方案2】：

您可以使用返回公会@everyone 角色的roles.everyone，也可以直接使用guild's ID。此外，您的覆盖不正确。它应该包含两个对象；一种拒绝所有人的观点，一种允许发送消息的成员观看。

其中任何一个都可以：

let permissionOverwrites = [
  {
    id: message.guild.roles.everyone.id,
    deny: ['VIEW_CHANNEL'],
  },
  {
    id: message.author.id,
    allow: ['VIEW_CHANNEL'],
  },
];

let channel = await guild.channels.create(
  `${message.author.username}-${message.author.discriminator}`,
  {
    parent: 'took out ID',
    topic: `Support for ${message.author.tag} | ID: ${message.author.id}`,
    permissionOverwrites,
  },
);

或者：

let permissionOverwrites = [
  {
    id: message.guild.id,
    deny: ['VIEW_CHANNEL'],
  },
  {
    id: message.author.id,
    allow: ['VIEW_CHANNEL'],
  },
];

let channel = await guild.channels.create(
  `${message.author.username}-${message.author.discriminator}`,
  {
    parent: 'took out ID',
    topic: `Support for ${message.author.tag} | ID: ${message.author.id}`,
    permissionOverwrites,
  },
);

【讨论】：