使用预先填写的新电话号码在 iOS 上打开 whatsapp

Question

我知道有一些与 whatsapp 通信的方案，例如：

NSURL *whatsappURL = [NSURL URLWithString:@"whatsapp://send?text=Hello%2C%20World!"];
if ([[UIApplication sharedApplication] canOpenURL: whatsappURL]) {
    [[UIApplication sharedApplication] openURL: whatsappURL];
}

但我找不到如何使用以前不存在的电话号码打开 whatsapp。

这是一个“联系我们”页面，如果我只能打开whatsapp而不能预先填写电话号码，那就没用了。我需要与whatsapp联系...

我想要做的事情存在吗？

Answer 1

预填电话号码和文字

   NSURL *whatsappURL = [NSURL URLWithString:@"https://api.whatsapp.com/send?phone=9530670491&text=hello"];
if ([[UIApplication sharedApplication] canOpenURL: whatsappURL]) {
    [[UIApplication sharedApplication] openURL: whatsappURL];
}

点击这里查看Swift

查看链接了解更多详情https://www.whatsapp.com/faq/en/general/26000030

Answer 2

根据Whatsapp documentation，您实际上需要在您的通讯录中有联系人才能从 url 方案中打开讨论。
所以对于你的问题

我尝试做的事情存在吗？

答案是：不。

Answer 3

您可以在答案上方找到该 whatsapp API 的文档。根据我自己的试验添加更多观点：

要与特定联系人直接沟通，您需要遵守该联系人。 ABID 是保存联系人时系统自动生成的参数。因此，如果您的联系人中没有保存号码，那么您将无法从您的应用程序中打开它。

我使用了一种解决方法。当您的应用程序第一次在设备中加载时，您会将联系我们的号码保存到地址簿中。成功保存号码后，您将在退货中获得 ABID。您可以使用该 ABID 来调用与该联系人的消息传递。

NSURL *whatsappURL = [NSURL URLWithString:@"whatsapp://send?abid=123&text=Hello%2C%20World!"];

Answer 4

如果有人在寻找 Swift 版本

static func triggerWhats(_ vc:UIViewController){
        let msg = "Hello! I have a question"
        let urlWhats = "whatsapp://send?phone=+6599999999&text=\(msg)"
        if let urlString = urlWhats.addingPercentEncoding(withAllowedCharacters: .urlQueryAllowed){
            if let whatsappURL = NSURL(string: urlString) {
                if UIApplication.shared.canOpenURL(whatsappURL as URL) {
                    _ = UIApplication.shared.open(whatsappURL as URL, options: [:], completionHandler: nil)
                } else {
                    // Cannot open whatsapp
                    ViewUtil().popAlertView(vc, title: "WhatsApp Support", message: "Please WhatsApp us at +65999999 if you have any questions", option: "Ok")
                }
            }
        }
    }

Answer 5

Swift 3.0 打开什么应用程序。

在 info.plist 文件中添加这一行

<key>LSApplicationQueriesSchemes</key>
<array>
       <string>whatsapp://</string>
</array>

func OpenWhatsApp(_ vc:UIViewController){
        let msg = "" // here pass your message 
        let urlWhats = "https://api.whatsapp.com/send?phone=(Mobileno)&text=\(msg)" // Mobile number that include country code and without + sign . 
        if let urlString = urlWhats.addingPercentEncoding(withAllowedCharacters: .urlQueryAllowed){
            if let whatsappURL = URL(string: urlString) {
                if UIApplication.shared.canOpenURL(whatsappURL) {
                    if #available(iOS 10.0, *) {
                        _ = UIApplication.shared.open(whatsappURL, options: [:], completionHandler: nil)
                    } else {
                        // Fallback on earlier versions
                        UIApplication.shared.canOpenURL(whatsappURL)
                    }
                } else {
                    // Cannot open whatsapp
                    AppUtilities.sharedInstance.showAlert(title: "WhatsApp Support", msg: "Your device is not support whats app")
                }
            }
        }
    }

Answer 6

对于 Swift 3.0 或更高版本，这将打开一个号码的 whatsapp 聊天

号码示例：“+918798766554”

if let whatappURL = URL(string: "https://api.whatsapp.com/send?phone=\(number)&text=\(msg)"),
  UIApplication.shared.canOpenURL(whatappURL)
{
  if #available(iOS 10.0, *) {
    UIApplication.shared.open(whatappURL, options: [:], completionHandler: nil)
  } else {
    UIApplication.shared.openURL(whatappURL)
  }
}

Answer 7

根据Whatsapp documentation

对于 Swift 3.0 或更高版本，这将打开一个号码的 whatsapp 聊天

数字示例：“+6599999999”

UIApplication.shared.open(URL(string: "https://wa.me/+6599999999")!)