以编程方式通过whatsapp发送消息

Question

我正在尝试通过 Whatsapp 以编程方式发送消息，除了用户需要单击发送按钮之外，该代码有效。我需要应用程序来做所有事情（所有用户交互）。一种方法如下。

转到菜单按钮 > 设置 > 聊天。并检查“输入是发送选项”

这是我正在使用的代码：

protected void sendwts(){
    String smsNumber = "2126123456789"; // E164 format without '+' sign
    Intent sendIntent = new Intent(Intent.ACTION_SEND);
    //  Intent sendIntent = new Intent(Intent.ACTION_SENDTO);
    sendIntent.setType("text/plain");
    sendIntent.putExtra(Intent.EXTRA_TEXT, "test \n");
    sendIntent.putExtra("jid", smsNumber + "@s.whatsapp.net"); //phone number without "+" prefix
    sendIntent.setPackage("com.whatsapp");

    startActivity(sendIntent);
}

谢谢

Answer 1

您只能使用 Android 的 Accessibility API 来做到这一点。

这个想法很简单，你实际上会让 Android 执行点击 Whatsapp 的发送按钮。

所以流程将是：

1. 发送一条常规消息（包含您当前使用的意图），并在消息内容的末尾添加一个后缀，例如“Sent by MY_APP”。
2. 一旦出现文字，您的无障碍服务将收到通知，whatsapp 的EditText 已填满。
3. 如果后缀出现在 whatsapp 的 EditText 上，您的无障碍服务将点击发送按钮。 （这是为了避免在用户键入常规消息时执行操作）。

这是一个示例（如果您想使其更具限制性，您可以对其进行调整）：

public class WhatsappAccessibilityService extends AccessibilityService {

    @Override
    public void onAccessibilityEvent (AccessibilityEvent event) {
        if (getRootInActiveWindow () == null) {
            return;
        }

        AccessibilityNodeInfoCompat rootInActiveWindow = AccessibilityNodeInfoCompat.wrap (getRootInActiveWindow ());

        // Whatsapp Message EditText id
        List<AccessibilityNodeInfoCompat> messageNodeList = rootInActiveWindow.findAccessibilityNodeInfosByViewId ("com.whatsapp:id/entry");
        if (messageNodeList == null || messageNodeList.isEmpty ()) {
            return;
        }

        // check if the whatsapp message EditText field is filled with text and ending with your suffix (explanation above)
        AccessibilityNodeInfoCompat messageField = messageNodeList.get (0);
        if (messageField.getText () == null || messageField.getText ().length () == 0 
            || !messageField.getText ().toString ().endsWith (getApplicationContext ().getString (R.string.whatsapp_suffix))) { // So your service doesn't process any message, but the ones ending your apps suffix
            return;
        }

        // Whatsapp send button id
        List<AccessibilityNodeInfoCompat> sendMessageNodeInfoList = rootInActiveWindow.findAccessibilityNodeInfosByViewId ("com.whatsapp:id/send");
        if (sendMessageNodeInfoList == null || sendMessageNodeInfoList.isEmpty ()) {
            return;
        }

        AccessibilityNodeInfoCompat sendMessageButton = sendMessageNodeInfoList.get (0);
        if (!sendMessageButton.isVisibleToUser ()) {
            return;
        }

        // Now fire a click on the send button
        sendMessageButton.performAction (AccessibilityNodeInfo.ACTION_CLICK);

        // Now go back to your app by clicking on the Android back button twice: 
        // First one to leave the conversation screen 
        // Second one to leave whatsapp
        try {
            Thread.sleep (500); // hack for certain devices in which the immediate back click is too fast to handle
            performGlobalAction (GLOBAL_ACTION_BACK);
            Thread.sleep (500);  // same hack as above
        } catch (InterruptedException ignored) {}
        performGlobalAction (GLOBAL_ACTION_BACK);
    }
}

然后在res -> xml -> whatsapp_service.xml中创建它的定义：

<?xml version="1.0" encoding="utf-8"?>
<accessibility-service
    xmlns:android="http://schemas.android.com/apk/res/android"
    android:accessibilityEventTypes="typeWindowContentChanged"
    android:packageNames="com.whatsapp"
    android:accessibilityFeedbackType="feedbackSpoken"
    android:notificationTimeout="100"
    android:canRetrieveWindowContent="true"/>

然后在你的清单中声明它：

<service
    android:name=".services.WhatsappAccessibilityService"
    android:label="Accessibility Service"
   android:permission="android.permission.BIND_ACCESSIBILITY_SERVICE">
    <meta-data
        android:name="android.accessibilityservice"
        android:resource="@xml/whatsapp_service"/>

    <intent-filter>
        <action android:name="android.accessibilityservice.AccessibilityService"/>
    </intent-filter>
</service>

最后，检查是否为您的应用启用了无障碍服务，如果没有，则将用户重定向到设置：

private boolean isAccessibilityOn (Context context, Class<? extends AccessibilityService> clazz) {
    int accessibilityEnabled = 0;
    final String service = context.getPackageName () + "/" + clazz.getCanonicalName ();
    try {
        accessibilityEnabled = Settings.Secure.getInt (context.getApplicationContext ().getContentResolver (), Settings.Secure.ACCESSIBILITY_ENABLED);
    } catch (Settings.SettingNotFoundException ignored) {  }

    TextUtils.SimpleStringSplitter colonSplitter = new TextUtils.SimpleStringSplitter (":");

    if (accessibilityEnabled == 1) {
        String settingValue = Settings.Secure.getString (context.getApplicationContext ().getContentResolver (), Settings.Secure.ENABLED_ACCESSIBILITY_SERVICES);
        if (settingValue != null) {
            colonSplitter.setString (settingValue);
            while (colonSplitter.hasNext ()) {
                String accessibilityService = colonSplitter.next ();

                if (accessibilityService.equalsIgnoreCase (service)) {
                    return true;
                }
            }
        }
    }

    return false;
}

你会打电话给：

if (!isAccessibilityOn (context, WhatsappAccessibilityService.class)) {
    Intent intent = new Intent (Settings.ACTION_ACCESSIBILITY_SETTINGS);
    context.startActivity (intent);
}

---

这纯粹是解决方案的技术方面。

现在，“你应该那样做吗？”的伦理问题，我相信答案很明确：

除非您针对的是残障人士（这正是 Accessibility API 的目的），否则您可能不应该这样做。