如何同时使用不和谐机器人命令和事件？

Question

我需要制作一个机器人来侦听服务器中写入的消息，同时接受命令。

# Create the Discord client
client = discord.Client()
client = commands.Bot(command_prefix = '!')
client.remove_command('help')

@client.event
async def on_ready():
    print('ready')


@client.event                                               #ricerca messaggi 
async def on_message(message):
    # Ignore messages made by the bot
    if(message.author == client.user):
        return
    a = ''
    a += message.embeds[0]["description"]
    if a == 'abcdef':
        print(' aaaaa ')



@client.command()
async def hello():
    await client.say('hello')


client.run('token')

我怎样才能让它工作？ 我认为问题在于机器人在第一个事件中继续循环...... 我读过关于 sub_process 但我不明白如何使用它。

Answer 1

而不是@client.event()，只需执行@client.listen()，它应该可以工作并删除client = discord.Client()

Answer 2

您需要在 on_message 末尾添加 process_commands()。 This is because overriding the default on_message forbids commands from running.

@client.event                                               #ricerca messaggi 
async def on_message(message):
    # Ignore messages made by the bot
    if(message.author == client.user):
        return
    a = ''
    a += message.embeds[0]["description"]
    if a == 'abcdef':
        await message.channel.send(' aaaaa ')
    await client.process_commands(message)