如何让机器人在出错后不停止？不和谐.js

Question

我有脚本必须有理由踢用户。

语法：

$kick @user 原因

但是当我输入时：

$kick sometext nexttext

我在控制台中遇到错误：

TypeError: Cannot read property 'kick' of undefined

然后机器人停止...

如何编辑此脚本，以便在输入错误值后不会弹出错误关闭机器人并且机器人将向通道发送消息，例如。 “值不正确”？

脚本：

const discord = require('discord.js');
const client = new discord.Client;
const prefix = "$";
 client.on('message', function(message) {
const args = message.content.slice(prefix.length).trim().split(/ +/g);

const command = args.shift().toLowerCase();

if(command === "kick") {

 let member = message.mentions.members.first();
 let reason = args.slice(1).join(" ");
  member.kick(reason);
  message.delete();
  client.channels.cache.get('737341022782357566').send("User <@" + member.id + "> with id " + member.id + " has been kicked by <@" + message.author.id + "> with reason " + reason)  

}})
client.login('token');

Answer 1

在javascript中执行有机会崩溃的代码，你可以使用statment

try {
//code to test
} catch(err) {
//code if it crash
}

Answer 2

添加if (member) 以测试是否有人提及。

在 else 中，您可以发送“错误命令”消息

如果消息以您的前缀开头，您也应该只触发机器人

const discord = require('discord.js');
const client = new discord.Client;
const prefix = "$";

client.on('message', function(message) {
  if (!message.content.startsWith(prefix)) { return } 
  //this line prevents the bot to execute every message
  const args = message.content.slice(prefix.length).trim().split(/ +/g);

  const command = args.shift().toLowerCase();

  if(command === "kick") {

    let member = message.mentions.members.first();
    let reason = args.slice(1).join(" ");
    if (member) { // add this
      member.kick(reason);
      client.channels.cache.get('737341022782357566').send(`User ${member.user} with id: ${member.id} has been kicked by ${message.author} with reason: ${reason}`); 
    } else {
      message.reply("invalid parameters for $kick")
    }

    message.delete();
  }
})

client.login('token');