【发布时间】:2020-01-01 11:15:29
【问题描述】:
如何在不将歌曲下载为文件的情况下使用 Youtube 上的不和谐机器人播放音乐?
我已经查看了 discord.py 文档中包含的音乐机器人,但它会将文件下载到目录中。有没有办法避免这种情况?文档示例中的代码:
ytdl_format_options = {
'format': 'bestaudio/best',
'outtmpl': '%(extractor)s-%(id)s-%(title)s.%(ext)s',
'restrictfilenames': True,
'noplaylist': True,
'nocheckcertificate': True,
'ignoreerrors': False,
'logtostderr': False,
'quiet': True,
'no_warnings': True,
'default_search': 'auto',
'source_address': '0.0.0.0' # bind to ipv4 since ipv6 addresses cause issues sometimes
}
ffmpeg_options = {
'options': '-vn'
}
ytdl = youtube_dl.YoutubeDL(ytdl_format_options)
class YTDLSource(discord.PCMVolumeTransformer):
def __init__(self, source, *, data, volume=0.5):
super().__init__(source, volume)
self.data = data
self.title = data.get('title')
self.url = data.get('url')
@classmethod
async def from_url(cls, url, *, loop=None, stream=False):
loop = loop or asyncio.get_event_loop()
data = await loop.run_in_executor(None, lambda: ytdl.extract_info(url, download= not stream))
if 'entries' in data:
# take first item from a playlist
data = data['entries'][0]
filename = data['url'] if stream else ytdl.prepare_filename(data)
return cls(discord.FFmpegPCMAudio(filename, **ffmpeg_options), data=data)
@client.command()
async def play(ctx, url):
voice = await ctx.author.voice.channel.connect()
player = await YTDLSource.from_url(url, loop=client.loop)
ctx.voice_client.play(player, after=lambda e: print('Player error: %s' % e) if e else None)
【问题讨论】:
-
如果不下载字节就无法播放。这是不可能的。
-
我猜你只是想下载而不保存字节,但你仍然需要先下载。
标签: python-3.x discord.py-rewrite