C++ For 循环和数组混淆

Question

我昨天刚开始我的 C++ 课，我在适应这门语言时遇到了一些困难。我正在尝试完成一个二次公式计算器，使用五个不同的用户给定系数（然后将其放入数组中），用于计算根，然后将较小的根（来自五个方程）放入一个新数组中。

我没有得到的是如何使用现在放入数组中的系数来计算根，以及较小根的计算。到目前为止我的代码（我只是在修改主函数）：

#include <iostream>
#include <cmath> 
#include <cstdlib>


// True if candidate root is a root of the polynomial a*x*x + b*x + c = 0 
bool check_root(int a, int b, int c, float root) {  
  // plug the value into the formula
  float check = a * root * root + b * root + c;
  // see if the absolute value is zero (within a small tolerance)
  if (fabs(check) > 0.0001) {
    std::cerr << "ERROR:  " << root << " is not a root of this formula." << std::endl;
    return false;
  } else {
    return true;
  }
}

/* Use the quadratic formula to find the two real roots of polynomial.   Returns 
true if the roots are real, returns false if the roots are imaginary.  If the roots 
are real, they are returned through the reference parameters root_pos and root_neg. */ 
bool find_roots(int a, int b, int c, float &root_pos, float &root_neg) {
  // compute the quantity under the radical of the quadratic formula
  int radical = b*b - 4*a*c;
  // if the radical is negative, the roots are imaginary
  if (radical < 0) {
    std::cerr << "ERROR:  Imaginary roots" << std::endl;
    return false;
  }
  float sqrt_radical = sqrt(radical);  
  // compute the two roots
  root_pos = (-b + sqrt_radical) / float(2*a);
  root_neg = (-b - sqrt_radical) / float(2*a);
  return true;
}

int main() {
  int b_array[5];
  int c_array[5];
  int smaller_root[5];
  for (int i=0;i<5;i++){
    std::cout << "Enter a 'b' coefficient for the quadratic function: a*x*x + b*x + c = 0" << std::endl;
    int b;
    std::cin >> b;
    b_array[i] = b;
  }
  for (int i=0;i<5;i++){
    std::cout << "Enter a 'c' coefficient for the quadratic function: a*x*x + b*x + c = 0" << std::endl;
    int c;
    std::cin >> c;
    c_array[i] = c;
  }
  for (int i=0;i<5;i++){
    float root_1, root_2;
    bool success = find_roots(1,b_array[i],c_array[i], root_1,root_2);
    if (root_1>root_2) 
        smaller_root[i] = root_1;
    if (root_2>root_1)
        smaller_root[i] = root_2;
    } else {
      std::cerr << "ERROR:  Unable to verify one or both roots." << std::endl; 
    }
  }
  return 0; 
}

谢谢！

Answer 1

不应该这样吗：

if (root_1>root_2) 
    smaller_root[i] = root_1;
if (root_2>root_1)
    smaller_root[i] = root_2;
} else {
  std::cerr << "ERROR:  Unable to verify one or both roots." << std::endl; 
}

是

if (root_1>root_2) {
    smaller_root[i] = root_1;
} else
if (root_2>root_1) {
    smaller_root[i] = root_2;
} else {
  std::cerr << "ERROR:  Unable to verify one or both roots." << std::endl;
}

我认为'else'之前的大括号正在关闭for循环 }