REPL - 重新定义后恢复可调用

Question

我在 Python REPL 中做了一些工作，并重新定义了一个原始可调用对象。

即list = [] 将阻止tuple = list((1,2,3)) 继续工作。

除了重新启动 REPL 之外，还有没有办法“恢复”或将列表重新分配为其默认值？

也许有导入或超类？或者它会永远丢失并坚持我分配的内容，直到我重新启动 REPL？

Answer 1

您可以删除名称del list

In [9]: list = []    
In [10]: list()
---------------------------------------------------------------------------
TypeError                                 Traceback (most recent call last)
<ipython-input-10-8b11f83c3293> in <module>()
----> 1 list()

TypeError: 'list' object is not callable    
In [11]: del list    
In [12]: list()
Out[12]: []

或者list = builtins.list 用于python3：

In [10]: import builtins
In [11]: list = []    
In [12]: list()
---------------------------------------------------------------------------
TypeError                                 Traceback (most recent call last)
<ipython-input-12-8b11f83c3293> in <module>()
----> 1 list()

TypeError: 'list' object is not callable    
In [13]: list = builtins.list    
In [14]: list()
Out[14]: []

对于python 2：

In [1]: import __builtin__    
In [2]: list = []    
In [3]: list()
---------------------------------------------------------------------------
TypeError                                 Traceback (most recent call last)
<ipython-input-3-8b11f83c3293> in <module>()
----> 1 list()    
TypeError: 'list' object is not callable  
In [4]: list = __builtin__.list  
In [5]: list()
Out[5]: []