【发布时间】:2018-11-25 10:36:43
【问题描述】:
我有一个对象数组,我使用 *ngfor 循环并显示在 ngdropdownmenu 中。我选择一个并返回一个包含名称和操作的对象并将其分配给字符串变量。 如何在打字稿中只获取所选对象的动作值?
//Typescript Code:
specificaction: string = "";
public finishActions = [
{ name: "blah", action: "blahblahblah" },
{ name: "blah", action: "blahblahblah" },
{ name: "blah", action: "blahblahblah" },
{ name: "blah", action: "blahblahblah" },
{ name: "blah", action: "blahblahblah" },
{ name: "", action: "" }
]
finishAction(action: string) {
this.specificaction= action;
//I CAN NOT GET THE specification.action
console.log(this.specificaction.action);
}
//HTML
<div ngbDropdownMenu aria-labelledby="dropdownBasic1">
<button class="dropdown-item text-right" *ngFor="let action of
finishActions" (click)="finishAction(action)">{{action.name}}</button>
</div>
【问题讨论】:
-
如果您已经拥有该对象,只需获取其属性,例如
item.action。
标签: arrays json typescript object