这是我的问题的部分、幼稚的解决方案 - 我会在进一步开发时更新它。
function findDifferences(objectA, objectB) {
var propertyChanges = [];
var objectGraphPath = ["this"];
(function(a, b) {
if(a.constructor == Array) {
// BIG assumptions here: That both arrays are same length, that
// the members of those arrays are _essentially_ the same, and
// that those array members are in the same order...
for(var i = 0; i < a.length; i++) {
objectGraphPath.push("[" + i.toString() + "]");
arguments.callee(a[i], b[i]);
objectGraphPath.pop();
}
} else if(a.constructor == Object || (a.constructor != Number &&
a.constructor != String && a.constructor != Date &&
a.constructor != RegExp && a.constructor != Function &&
a.constructor != Boolean)) {
// we can safely assume that the objects have the
// same property lists, else why compare them?
for(var property in a) {
objectGraphPath.push(("." + property));
if(a[property].constructor != Function) {
arguments.callee(a[property], b[property]);
}
objectGraphPath.pop();
}
} else if(a.constructor != Function) { // filter out functions
if(a != b) {
propertyChanges.push({ "Property": objectGraphPath.join(""), "ObjectA": a, "ObjectB": b });
}
}
})(objectA, objectB);
return propertyChanges;
}
这里是如何使用它的示例以及它将提供的数据（请原谅这个冗长的示例，但我想使用一些相对不平凡的东西）：
var person1 = {
FirstName : "John",
LastName : "Doh",
Age : 30,
EMailAddresses : [
"john.doe@gmail.com",
"jd@initials.com"
],
Children : [
{
FirstName : "Sara",
LastName : "Doe",
Age : 2
}, {
FirstName : "Beth",
LastName : "Doe",
Age : 5
}
]
};
var person2 = {
FirstName : "John",
LastName : "Doe",
Age : 33,
EMailAddresses : [
"john.doe@gmail.com",
"jdoe@hotmail.com"
],
Children : [
{
FirstName : "Sara",
LastName : "Doe",
Age : 3
}, {
FirstName : "Bethany",
LastName : "Doe",
Age : 5
}
]
};
var differences = findDifferences(person1, person2);
此时，如果您将differences 数组序列化为 JSON，则如下所示：
[
{
"Property":"this.LastName",
"ObjectA":"Doh",
"ObjectB":"Doe"
}, {
"Property":"this.Age",
"ObjectA":30,
"ObjectB":33
}, {
"Property":"this.EMailAddresses[1]",
"ObjectA":"jd@initials.com",
"ObjectB":"jdoe@hotmail.com"
}, {
"Property":"this.Children[0].Age",
"ObjectA":2,
"ObjectB":3
}, {
"Property":"this.Children[1].FirstName",
"ObjectA":"Beth",
"ObjectB":"Bethany"
}
]
Property 值中的this 指的是被比较对象的根。所以，这个解决方案还不是完全我需要的，但它非常接近。
希望这对那里的人有用，如果您有任何改进建议，我会全力以赴；我昨晚很晚才写的（即今天凌晨），可能有些事情我完全忽略了。
谢谢。