【发布时间】:2018-08-13 10:24:10
【问题描述】:
我有一个看起来像这样的 Firebase 数据库(Json):
{
"user" : {
"UVHpZfD60EWcYDbeV60ENqXaioA3" : {
"email" : "thisisanothertest@gg.gg",
"location" : {
"latitude" : 37.785834,
"longitude" : -122.406417
},
"profile" : {
"alter" : "23",
"geschlecht" : "männlich",
"name" : "Mario1"
}
},
"nEsKd9uIOnSmVuMbAK0K2X1Dz6A3" : {
"email" : "thisisatest@gg.gg",
"location" : {
"latitude" : 37.785834,
"longitude" : -122.406417
},
"profile" : {
"alter" : "23",
"geschlecht" : "männlich ",
"name" : "Mario"
}
}
}
问题: 现在我想从所有用户(纬度和经度)那里获取位置,以便稍后将它们放在地图上。 通过执行以下代码,我可以很容易地获得单个用户的位置。但是我怎样才能一次从所有用户那里获取数据呢?
var ref: DatabaseReference!
ref = Database.database().reference()
let userID = Auth.auth().currentUser?.uid
ref.child("user").child(userID!).child("location").observeSingleEvent(of: .value, with: { (snapshot) in
// Get user value
let value = snapshot.value as? NSDictionary
let lat = value?["latitude"] as? Double ?? 0.0
let long = value?["longitude"] as? Double ?? 0.0
我已经发现了一个类似的问题here
所以我尝试了上面链接中的代码:
let usersRef = ref.child("users")
usersRef.observeSingleEvent(of: .value, with: { (snapshot) in
for snap in snapshot.children {
let userSnap = snap as! FIRDataSnapshot
let uid = userSnap.key //the uid of each user
let userDict = userSnap.value as! [String:AnyObject] //child data
let location = userDict["Location"] as! String
print("key = \(uid) is at location = \(location)")
}
})
但是用那段代码我只能得到所有的电子邮件地址。通过将“位置”更改为“电子邮件”。如何再下一个节点访问“位置”节点并获取所有用户的纬度和经度?
谢谢你:)
【问题讨论】:
标签: swift firebase firebase-realtime-database