过滤、连接和修改两个数组

Question

我在Typescript中有一个项目，我想在其中考虑一个字段的信息来连接两个数组，即如果该字段的值匹配，则删除一个并合并该数组的数据。

这些是我的arrays：

let sheet = [ { fecDate: date,
    codCountry: 'CO',
    fileName: 'CO_SER.txt',
    ftpExists: 0,
    sheetExists: 1 },
{ fecDate: date,
    codCountry: 'CO',
    fileName: 'CO_DAT.txt',
    ftpExists: 0,
    sheetExists: 1 } ]
    
let ftp = [ { fecDate: date,
    codCountry: 'CO',
    fileName: 'CO_SER.txt',
    ftpExists: 1,
    sheetExists: 0 },
{ fecDate: date,
    codCountry: 'CO',
    fileName: 'CO_PRU.txt',
    ftpExists: 1,
    sheetExists: 0 } ]

这就是我想要实现的目标：

let result = [ { fecDate: date,
    codCountry: 'CO',
    fileName: 'CO_SER.txt',
    ftpExists: 1,
    sheetExists: 1 },
{ fecDate: date,
    codCountry: 'CO',
    fileName: 'CO_DAT.txt',
    ftpExists: 0,
    sheetExists: 1 },
{ fecDate: date,
    codCountry: 'CO',
    fileName: 'CO_PRU.txt',
    ftpExists: 1,
    sheetExists: 0 } ]

这是我到目前为止的代码，目前我只设法过滤不在另一个数组中的数据：

let onlyFtp = ftp.filter(await this.objectComparer(sheet, ftp, 'fileName'));
let onlySheet = sheet.filter(await this.objectComparer(ftp, sheet, 'fileName'));

public async objectComparer(fstArr: any, secArr: any) {
    try {

        let only = fstArr.filter(
          (fstItem: any) => !secArr.some((secItem: any) => fstItem[key] === secItem[key])
        );
        
        return only;
      
    } catch (error) {
        return Promise.reject(error);
    }  
}

onlyFtp = [{ fecDate: date,
    codCountry: 'CO',
    fileName: 'CO_PRU.txt',
    ftpExists: 1,
    sheetExists: 0 } ]
    
onlySheet = [{ fecDate: date,
    codCountry: 'CO',
    fileName: 'CO_DAT.txt',
    ftpExists: 0,
    sheetExists: 1 } ]

这样我得到了不变的数组，所以我只需要更新文件名为“CO_SER.txt”的数组

我的问题：我需要把fileName字段重复的数组去掉，但是不知道如何合并两个数组并更改对应的属性

Answer 1

使用 for 循环连接两个数组并合并 -

const date = '12/07/2021';
const sheet = [{
    fecDate: date,
    codCountry: 'CO',
    fileName: 'CO_SER.txt',
    ftpExists: 0,
    sheetExists: 1
  },
  {
    fecDate: date,
    codCountry: 'CO',
    fileName: 'CO_DAT.txt',
    ftpExists: 0,
    sheetExists: 1
  }
];

const ftp = [{
    fecDate: date,
    codCountry: 'CO',
    fileName: 'CO_SER.txt',
    ftpExists: 1,
    sheetExists: 0
  },
  {
    fecDate: date,
    codCountry: 'CO',
    fileName: 'CO_PRU.txt',
    ftpExists: 1,
    sheetExists: 0
  }
];

const merged = [...sheet, ...ftp];
const result = [];
for (const item of merged) {
  const existingItem = result.find(f => f.fileName == item.fileName);
  if (!existingItem) {
    result.push(item);
  } else {
    existingItem.ftpExists |= item.ftpExists;
    existingItem.sheetExists |= item.sheetExists;
  }
}
console.log(result);

Answer 2

使用地图（唯一键）
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Map

let sheet = [ { fecDate: '',
    codCountry: 'CO',
    fileName: 'CO_SER.txt',
    ftpExists: 0,
    sheetExists: 1 },
{ fecDate: '',
    codCountry: 'CO',
    fileName: 'CO_DAT.txt',
    ftpExists: 0,
    sheetExists: 1 } ]
    
let ftp = [ { fecDate: '',
    codCountry: 'CO',
    fileName: 'CO_SER.txt',
    ftpExists: 1,
    sheetExists: 0 },
{ fecDate: '',
    codCountry: 'CO',
    fileName: 'CO_PRU.txt',
    ftpExists: 1,
    sheetExists: 0 } ]
    
const map = new Map([...sheet, ...ftp].map(i => [i.fileName, i]))

// assuming sheets array sets sheetExists property
sheet.forEach(item => {
  // map.get(item.fileName).sheetExists = 1
  // edit:
  const mapItem = map.get(item.fileName)
  mapItem.ftpExists = mapItem.ftpExists || item.ftpExists
  mapItem.sheetExists = mapItem.sheetExists || item.sheetExists
})

const result = Array.from(map.values())
console.log(result)