删除自定义停用词形成python中的短语

Question

我正在尝试在进一步处理输入之前从用户输入中删除某些短语和单词，并且在尝试执行此操作时遇到了“索引超出范围”错误的问题并且完全卡住了。我该如何解决这个问题？ 我将输入短语作为字符串转换为列表以比较每个单词，并将停用词作为预定义列表。
示例输入：
[“好”、“你”、“知道”、“那个”、“天气”、“是”、“糟糕”]
["you", "know", "what", "i", "mean", "so", "just", "turn", "the", "lights", "on"]

#Gets user input and removes the selected stop words from it and returns a filtered phrase back.    
def stop_word_remover(phrase_list):

    stop_words_lst = ["yo", "so", "well", "um", "a", "the","you know", "i mean"]

    #initalize clean phrase string
    clean_input_phrase= ""

    #copying phrase_list into a new variable for stopword removal.
    Copy_phrase_list = list(phrase_list)

    #Cleanup loop

    for i in range(1,len(phrase_list)):
        has_stop_words = False

        for x in range(len(stop_words_lst)):
            has_stop_words = False

            #if one of the stop words matches the word passed by the first main loop      the  flag is raised.
            if (phrase_list[i-1]+" "+phrase_list[i]) == stop_words_lst[x].strip():
                has_stop_words = True    

            # this if statement adds the word of the phrase only if the flag is not raised thus making sure all the stop words are filtered out         
            if has_stop_words == True:
                Copy_phrase_list.remove(Copy_phrase_list[i-1])
                Copy_phrase_list.remove(Copy_phrase_list[i-1])

    #first for loop takes a individual words of the phrase given and makes a loop until the whole phrase goes through one word at a time
    for i in range(len(Copy_phrase_list)):
        #flag initialized for marking stop words
        has_stop_words = False

        #second loop takes all the stop words and compares them to the first word passed on by the first loop to sheck for a stop word
        for x in range(len(stop_words_lst)):
            #if one of the stop words matches the word passed by the first main loop the  flag is raised.
            if Copy_phrase_list[i] == stop_words_lst[x].strip():
            has_stop_words = True    

        # this if statement adds the word of the phrase only if the flag is not raised thus making sure all the stop words are filtered out        
        if has_stop_words == False:
            clean_input_phrase += str(Copy_phrase_list[i]) +" "


return clean_input_phrase

Answer 1

使用正则表达式替换功能。 用空字符串替换每个匹配项。

stop_words_lst = ['yo', 'so', 'well', 'um', 'a', 'the', 'you know', 'i mean']
s = "you know what i mean so just turn the lights on"

import re
for w in stop_words_lst:
    pattern = r'\b'+w+r'\b'
    s = re.sub(pattern, '', s)
    print (s)

Answer 2

您需要分开您的单词列表。一个应该用于单个单词，另一个应该用于短语。

single_word_list = ["yo", "so", "well", "um", "a", "the"]
phrase_list = ["you know", "i mean"]
for index, word in enumerate(Copy_phrase_list) :
    if word in single_word_lst:
        del Copy_phrase_list[index] 
    if word + " " + Copy_phrase_list[index+1] in phrase_list:
        del Copy_phrase_list[index] 
        del Copy_phrase_list[index+1] 
return " ".join(Copy_phrase_list) 

然后您需要将 copy_phrase_list 转换为字符串并返回。