在显示数据的 gridview 中需要帮助

Question

我想在 gridview 中显示我在运行时插入的所有数据。为此，我编写了代码但收到此错误。

"DataSource 和 DataSourceID 都是 在“GridView1”上定义。删除一个 定义。”

protected void Page_Load(object sender, EventArgs e)
{
    if (!Page.IsPostBack)
    {
        BindData();
    }
}

public void BindData()
{
     string str = ConfigurationManager.ConnectionStrings["ConnectionString"].ConnectionString.ToString();
     SqlConnection con = new SqlConnection(str);
     SqlDataAdapter da = new SqlDataAdapter("select * from Items where ItemId='" + TxtItemId.Text + "'", con);
     DataSet ds = new DataSet();
     da.Fill(ds,"Items");
     GridView1.DataSource = ds;         
     GridView1.DataBind();
}

请修改我的代码我的错误在哪里。

谢谢， 苏米特

Answer 1

点击按钮插入数据

SqlConnection con = new SqlConnection("connection string");
        SqlDataAdapter myadp = new SqlDataAdapter();
        myadp.InsertCommand = new SqlCommand();
        myadp.InsertCommand.Connection = con;
        con.Open();
        myadp.InsertCommand.CommandText = "insert into number values(@Silver)";
        myadp.InsertCommand.Parameters.AddWithValue("@Silver", TextBox10.Text);
        int i = myadp.InsertCommand.ExecuteNonQuery();
        if (i == 1)
        {
           // Response.Write("<script>alert('number updated sucessfully')</script>");
            Label2.Text = "Number updated sucessfully".ToString();
            TextBox10.Text = "";
        }
        else
        {
            //Response.Write("<script>alert('somthing went wrong try again')</script>");
            Label2.Text = "somthing went wrong try again".ToString();
        }
        con.Close();
        Responce.Redirect("your page.aspx");

在网格视图上显示数据

SqlCommand command = new SqlCommand("SELECT * from number");
SqlDataAdapter da = new SqlDataAdapter(command);
DataTable dt = new DataTable();
da.Fill(dt);
GridView1.DataSource = dt;
GridView1.DataBind(); 

所以整体编码将是

SqlConnection con = new SqlConnection("connection string");
        SqlDataAdapter myadp = new SqlDataAdapter();
        myadp.InsertCommand = new SqlCommand();
        myadp.InsertCommand.Connection = con;
        con.Open();
        myadp.InsertCommand.CommandText = "insert into number values(@Silver)";
        myadp.InsertCommand.Parameters.AddWithValue("@Silver", TextBox10.Text);
        int i = myadp.InsertCommand.ExecuteNonQuery();
        if (i == 1)
        {
           // Response.Write("<script>alert('number updated sucessfully')</script>");
            Label2.Text = "Number updated sucessfully".ToString();
            TextBox10.Text = "";
        }
        else
        {
            //Response.Write("<script>alert('somthing went wrong try again')</script>");
            Label2.Text = "somthing went wrong try again".ToString();
        }
        con.Close();
        Responce.Redirect("your page.aspx");
To display data on the grid view

    SqlCommand command = new SqlCommand("SELECT * from number");
    SqlDataAdapter da = new SqlDataAdapter(command);
    DataTable dt = new DataTable();
    da.Fill(dt);
    GridView1.DataSource = dt;
    GridView1.DataBind();



here the Responce.Redirect("your page.aspx"); will do the trick for you 

Answer 2

你需要在sql命令中使用SqlParameter。

你缺少逻辑。首先，当表单加载时，您需要将完整的项目表数据绑定到您的网格，十您将有一个文本框和按钮来过滤网格。

这是您的完整代码。用它。 100% 有效。

    <div id = "dvFilterGrid">
       Filter Grid :  <asp:TextBox ID="txtFilter" runat="server"></asp:TextBox>
        &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;
        <asp:Button ID="btnFilterGrid" runat="server" Text="Find" 
            onclick="btnFilterGrid_Click" />
    </div>

还有你的代码

public partial class _Default : System.Web.UI.Page
{
        SqlConnection con = new SqlConnection(ConfigurationManager.ConnectionStrings["ConnectionString"].ToString());
    protected void Page_Load(object sender, EventArgs e)
    {
        if (!IsPostBack)
        {
            BindGridData();
        }
    }

    protected void BindGridData()
    {
        con.Open();
        using (SqlCommand cmd = new SqlCommand("Select * from Items", con))
        {
            SqlDataAdapter da = new SqlDataAdapter(cmd);
            DataTable dt = new DataTable();
            da.Fill(dt);
            GridView1.DataSource = dt;
            GridView1.DataBind();
        }
    }

    protected void btnFilterGrid_Click(object sender, EventArgs e)
    {
        int ItemId = Convert.ToInt32(txtFilter.Text.Trim());
        FilterData(ItemId);
    }

    private void FilterData(int ItemId)
    {
        string query = "select * from Items where ItemId=@ItemId ";
         SqlCommand cmd = new SqlCommand(query,con);
         cmd.Parameters.Add(new SqlParameter("@ItemId", ItemId));
         SqlDataAdapter da = new SqlDataAdapter(cmd);
         DataSet ds = new DataSet();
         da.Fill(ds,"Items");
         GridView1.DataSource = ds;         
         GridView1.DataBind();
    }
 }

Answer 3

这两个属性是互斥的（当你使用其中一个时，你不能使用另一个）：

1. DataSourceID 属性将与 DataSource 控件（ObjectDataSource、XmlDataSource、SqlDataSource 等）一起使用
2. DataSource 属性将与自定义对象/自定义数据绑定一起使用。

例子：

1. 数据源ID

   @asp:ObjectDataSource ID="ods1" runat="server" SelectMethod="Test" TypeName="TestBL" /@ @asp:GridView ID="gv1" runat="server" DataSourceID="ods1" /@

在这种情况下，数据绑定会自动发生

1. 数据源

   @asp:GridView ID="gv2" runat="server" %@

在你后面的代码中会有这样的东西：

overrides void OnLoad(..)
{
    List<DataObject> source = new List<DataObject>();
    source.Add(new DataObject(..));
    source.Add(new DataObject(..));
    source.Add(new DataObject(..));
    gv2.DataSource = source;
    gv2.DataBind();
}

请注意，我使用了@而不是尖括号。

Answer 4

您似乎想手动绑定数据源。从您的gridview 中删除设计视图中的DataSourceID 属性。应该是这样的：

<asp:GridView runat="server" ID="grid" DataSourceID="SqlDataSource1"></asp:GridView>

只需删除 DataSourceID="SqlDataSource1" 属性。