【发布时间】:2020-03-28 03:18:41
【问题描述】:
我是 Python 中 XGBoost 的新手,所以如果这里的答案很明显,我深表歉意,但我正在尝试使用 panda 数据帧并在 Python 中获取 XGBoost,以提供与使用 Scikit-Learn 包装器时相同的预测做同样的练习。到目前为止,我一直无法这样做。举个例子,这里我取 boston 数据集,转换为 panda 数据帧,对数据集的前 500 个观察值进行训练,然后预测最后 6 个。我首先使用 XGBoost,然后使用 Scikit-Learn 包装器和即使我将模型的参数设置为相同,我也会得到不同的预测。具体来说,数组预测看起来与数组预测非常不同(参见下面的代码)。任何帮助将不胜感激!
from sklearn import datasets
import pandas as pd
import xgboost as xgb
from xgboost.sklearn import XGBClassifier
from xgboost.sklearn import XGBRegressor
### Use the boston data as an example, train on first 500, predict last 6
boston_data = datasets.load_boston()
df_boston = pd.DataFrame(boston_data.data,columns=boston_data.feature_names)
df_boston['target'] = pd.Series(boston_data.target)
#### Code using XGBoost
Sub_train = df_boston.head(500)
target = Sub_train["target"]
Sub_train = Sub_train.drop('target', axis=1)
Sub_predict = df_boston.tail(6)
Sub_predict = Sub_predict.drop('target', axis=1)
xgtrain = xgb.DMatrix(Sub_train.as_matrix(), label=target.tolist())
xgtest = xgb.DMatrix(Sub_predict.as_matrix())
params = {'booster': 'gblinear', 'objective': 'reg:linear',
'max_depth': 2, 'learning_rate': .1, 'n_estimators': 500, 'min_child_weight': 3, 'colsample_bytree': .7,
'subsample': .8, 'gamma': 0, 'reg_alpha': 1}
model = xgb.train(dtrain=xgtrain, params=params)
predictions = model.predict(xgtest)
#### Code using Sk learn Wrapper for XGBoost
model = XGBRegressor(learning_rate =.1, n_estimators=500,
max_depth=2, min_child_weight=3, gamma=0,
subsample=.8, colsample_bytree=.7, reg_alpha=1,
objective= 'reg:linear')
target = "target"
Sub_train = df_boston.head(500)
Sub_predict = df_boston.tail(6)
Sub_predict = Sub_predict.drop('target', axis=1)
Ex_List = ['target']
predictors = [i for i in Sub_train.columns if i not in Ex_List]
model = model.fit(Sub_train[predictors],Sub_train[target])
predictions2 = model.predict(Sub_predict)
【问题讨论】:
标签: python scikit-learn xgboost