【发布时间】:2015-11-11 12:54:39
【问题描述】:
我使用的是 spark 1.4.1。当我尝试广播随机森林模型时,它向我显示此错误:
Traceback (most recent call last):
File "/gpfs/haifa/home/d/a/davidbi/codeBook/Nice.py", line 358, in <module>
broadModel = sc.broadcast(model)
File "/opt/apache/spark-1.4.1-bin-hadoop2.4_doop/python/lib/pyspark.zip/pyspark/context.py", line 698, in broadcast
File "/opt/apache/spark-1.4.1-bin-hadoop2.4_doop/python/lib/pyspark.zip/pyspark/broadcast.py", line 70, in __init__
File "/opt/apache/spark-1.4.1-bin-hadoop2.4_doop/python/lib/pyspark.zip/pyspark/broadcast.py", line 78, in dump
File "/opt/apache/spark-1.4.1-bin-hadoop2.4_doop/python/lib/pyspark.zip/pyspark/context.py", line 252, in __getnewargs__
Exception: It appears that you are attempting to reference SparkContext from a broadcast variable, action, or transforamtion. SparkContext can only be used on the driver, not in code that it run on workers. For more information, see SPARK-5063.
我尝试执行的代码示例:
sc = SparkContext(appName= "Something")
model = RandomForest.trainRegressor(sc.parallelize(data), categoricalFeaturesInfo=categorical, numTrees=100, featureSubsetStrategy="auto", impurity='variance', maxDepth=4)
broadModel= sc.broadcast(model)
如果有人可以帮助我,我将非常感激! 非常感谢!
【问题讨论】:
-
是否有需要广播整个模型的原因?该模型可以对输入的 RDD 进行预测。
-
有不止一个模型(在我的例子中,每个模型定义组)。每个样本都需要从每个模型中得到预测,才能知道他最喜欢哪个组。我正在处理大数据,所以我需要将模型广播到映射器。
标签: apache-spark pyspark broadcast random-forest apache-spark-mllib