试图填写班级列表

Question

我真的很抱歉我是一个初学者...... 最后，当它应该是 8 个不同的名称/角色时，我只有一个具有相同名称/位置的 8 个 TimeCardDayStrip 列表。 我不明白我在这里做错了什么： 非常感谢

'''
class TimeCardDayStrip {
  String name, position;
  DateTime day;

  @override
  String toString(){
    return '{ $this.name, $this.position }';
  }
}

void main() {
  var tcds = TimeCardDayStrip();
  var listOfTcds = [];
  List<String> names, roles;
   names = ["Michael", "Gunnell", "Byrne", "Aspromonte", "Davis", "Adam Jordan", "Mirko"];
  roles = ["Director", "Vice", "President", "1ST", "KEY 2ND", "2ND", "BASECAMP PA", "PA", " PA", "Add'l PA"];

  for (int i = 0; i < names.length; i++) {
    tcds.name = names[i];
    tcds.position = roles[i];
    listOfTcds.add(tcds);
    // checking the list as it creates
    print(listOfTcds[i].name+' is '+listOfTcds[i].position);
  }
  //print the list of card to check
  print('print the list of time card to check');
  for (int x = 0; x < listOfTcds.length; x++){
    print (listOfTcds.elementAt(x).name);
  }
}
'''

Answer 1

如果您只想打印出每个名称： 将其放入循环中（您应该在每个循环中创建新对象，而不是更新同一个对象）

 for (int i = 0; i < names.length; i++) {

    var tcds = TimeCardDayStrip();

    tcds.name = names[i];
    tcds.position = roles[i];
    listOfTcds.add(tcds);

    // checking the list as it creates
    print('${listOfTcds[i].name} is ${listOfTcds[i].position}');
}

后来

 listOfTcds[x].name 

如果你想展示东西：

  @override
  Widget build(BuildContext ctx) {
    return ListView.builder(
            itemCount: listOfTcds.length,
            itemBuilder: (context, index) {
              return CustomTile(item: listOfTcds[index]);
            },
          );
  }

Answer 2

我相信您需要将 tcds 声明为 Tcds = new TimecardDayStrip() 而不仅仅是 tcds = TimeCardDayStrip() 或者您只是更改同一个对象而不是创建新实例。