将数据框放入 randomForest pyspark

Question

我有一个DataFrame，看起来像这样：

+--------------------+------------------+
|            features|           labels |
+--------------------+------------------+
|[-0.38475, 0.568...]|          label1  |
|[0.645734, 0.699...]|          label2  |
|     .....          |          ...     |
+--------------------+------------------+

两列都是字符串类型 (StringType())，我想将其放入 spark ml randomForest 中。为此，我需要将特征列转换为包含浮点数的向量。有没有人知道怎么做？

Answer 1

如果您使用的是 Spark 2.x，我相信这就是您所需要的：

from pyspark.sql.functions import udf
from pyspark.mllib.linalg import Vectors
from pyspark.ml.linalg import VectorUDT
from pyspark.ml.feature import StringIndexer

df = spark.createDataFrame([("[-0.38475, 0.568]", "label1"), ("[0.645734, 0.699]", "label2")], ("features", "label"))

def parse(s):
  try:
    return Vectors.parse(s).asML()
  except:
    return None

parse_ = udf(parse, VectorUDT())

parsed = df.withColumn("features", parse_("features"))

indexer = StringIndexer(inputCol="label", outputCol="label_indexed")

indexer.fit(parsed).transform(parsed).show()
## +----------------+------+-------------+
## |        features| label|label_indexed|
## +----------------+------+-------------+
## |[-0.38475,0.568]|label1|          0.0|
## |[0.645734,0.699]|label2|          1.0|
## +----------------+------+-------------+

使用 Spark 1.6，并没有太大的不同：

from pyspark.sql.functions import udf
from pyspark.ml.feature import StringIndexer
from pyspark.mllib.linalg import Vectors, VectorUDT

df = sqlContext.createDataFrame([("[-0.38475, 0.568]", "label1"), ("[0.645734, 0.699]", "label2")], ("features", "label"))

parse_ = udf(Vectors.parse, VectorUDT())

parsed = df.withColumn("features", parse_("features"))

indexer = StringIndexer(inputCol="label", outputCol="label_indexed")

indexer.fit(parsed).transform(parsed).show()
## +----------------+------+-------------+
## |        features| label|label_indexed|
## +----------------+------+-------------+
## |[-0.38475,0.568]|label1|          0.0|
## |[0.645734,0.699]|label2|          1.0|
## +----------------+------+-------------+

Vectors 有一个parse 函数，可以帮助你实现你想要做的事情。