根据 Python 中的字典值分离输入数据

Question

需要分离输入数据，如果它在字典中存在/不存在：

输入文件：

1,aaaaaaaa3nawwqfzplgms3u4n7kobqq344sqkn3e75zpsek7kxgaskwsba
2,aaaaaaaa3nawwqfzplgms3u4n7kobqq344sqkn3e75zpsek7kxgaskwsba
3,aaaaaaaangdg77mg3cxnialazk7whbtdidftz3rv2bhqrxcvymaecagxdq
4,aaaaaaaa3nawwqfzplgms3u4n7kobqq344sqkn3e75zpsek7kxgaskwsba
5,aaaaaaaa3nawwqfzplgms3u4n7kobqq344sqkn3e75zpsek7kxgaskwsba
6,aaaaaatbmbxncexycbtsyrnhexniqr7g4vypfuksh5ezmzymuw7k2bw4sa
7,aaaaaatbmbxncexycbtsyrnhexniqr7g4vypfuksh5ezmzymuw7k2bw4sa 

根据 mapping_hash 从上述文件中分离数据的脚本

# Check if the col[2] in the file is part of this dictionary
mapping_hash = {"ad1": "aaaaaaaangdg77mg3cxnialazk7whbtdidftz3rv2bhqrxcvymaecagxdq",
           "ad2":"aaaaaaaa3nawwqfzplgms3u4n7kobqq344sqkn3e75zpsek7kxgaskwsba"}

absnt_dict= {}
Present_dict = {}

# Read the file
with open('so_input') as f:
    for row in f:
        row=row.strip().split(',')
        row_number = row[0]
        hash =row[1]
        print("--------------")
        
        for key, value in mapping_hash.items():
            #check if file value is part of mapping_hash dictionary
            if hash == value:
                print "Yes"
                Present_dict[row_number] = mapping_hash.keys()
            else:
                print "Na"
                absnt_dict[row_number] = hash

print Present_dict
print absnt_dict

输出：

--------------
Yes
Na
--------------
Yes
Na
--------------
Na
Yes
--------------
Yes
Na
--------------
Yes
Na
--------------
Na
Na
--------------
Na
Na

Row part of Hash:
    {'1': ['ad2', 'ad1'], '3': ['ad2', 'ad1'], '2': ['ad2', 'ad1'], '5': ['ad2', 'ad1'], '4': ['ad2', 'ad1']}
Row not part of Hash:    
{'1': 'aaaaaaaa3nawwqfzplgms3u4n7kobqq344sqkn3e75zpsek7kxgaskwsba', '3': 'aaaaaaaangdg77mg3cxnialazk7whbtdidftz3rv2bhqrxcvymaecagxdq', '2': 'aaaaaaaa3nawwqfzplgms3u4n7kobqq344sqkn3e75zpsek7kxgaskwsba', '5': 'aaaaaaaa3nawwqfzplgms3u4n7kobqq344sqkn3e75zpsek7kxgaskwsba', '4': 'aaaaaaaa3nawwqfzplgms3u4n7kobqq344sqkn3e75zpsek7kxgaskwsba', '7': 'aaaaaatbmbxncexycbtsyrnhexniqr7g4vypfuksh5ezmzymuw7k2bw4sa', '6': 'aaaaaatbmbxncexycbtsyrnhexniqr7g4vypfuksh5ezmzymuw7k2bw4sa'}

在这里，根据字典中元素的数量，循环将迭代并创建一个重复的条目！

1. 我希望 6 和 7 应该是 absnt_dict 的一部分，其余的都是 Present_dict 的一部分
2. 1 的输出应该是 ad2 不像列出两个值 '1': ['ad2', 'ad1']

Answer 1

这是因为即使遇到'Present'，你也会继续检查

Present_dict[row_number] = "Present"

所以所有的哈希都被插入到absnt_dict。

您应该改用会员检查

# Read the file
with open('so_input') as f:
    for row in f:
        row=row.strip().split(',')
        row_number = row[0]
        hash =row[1]
        print("--------------")

        if hash in mapping_hash.values():
                print "Yes"
                Present_dict[row_number] = "Present"
        else:
                print "Na"
                absnt_dict[row_number] = hash

结果：

{'1': 'Present', '3': 'Present', '2': 'Present', '5': 'Present', '4': 'Present'}
{'7': 'aaaaaatbmbxncexycbtsyrnhexniqr7g4vypfuksh5ezmzymuw7k2bw4sa', '6': 'aaaaaatbmbxncexycbtsyrnhexniqr7g4vypfuksh5ezmzymuw7k2bw4sa'}