ntile 函数在最新版本的 R 中不起作用答案

【问题标题】：ntile function not working in latest version of Rntile 函数在最新版本的 R 中不起作用
【发布时间】：2020-10-30 22:00:05
【问题描述】：

我的数据是

my_basket <- data.frame(ITEM_GROUP = c("Fruit","Fruit","Fruit","Fruit","Fruit","Vegetable","Vegetable","Vegetable","Vegetable","Dairy","Dairy","Dairy","Dairy","Dairy"), 
                       ITEM_NAME = c("Apple","Banana","Orange","Mango","Papaya","Carrot","Potato","Brinjal","Raddish","Milk","Curd","Cheese","Milk","Paneer"),
                       Price = c(100,80,80,90,65,70,60,70,25,60,40,35,50,120))

我想使用 ntile 函数计算百分位数列

df1 = mutate(my_basket, percentile_rank = ntile(my_basket$Price,100))

它应该给我一个看起来像 correct_df 的数据框

correct_df<- data.frame(ITEM_GROUP = c("Fruit","Fruit","Fruit","Fruit","Fruit","Vegetable","Vegetable","Vegetable","Vegetable","Dairy","Dairy","Dairy","Dairy","Dairy"), 
                       ITEM_NAME = c("Apple","Banana","Orange","Mango","Papaya","Carrot","Potato","Brinjal","Raddish","Milk","Curd","Cheese","Milk","Paneer"),
                       Price = c(100,80,80,90,65,70,60,70,25,60,40,35,50,120),
                       percentile_rank=c(86,65,72,79,43,51,29,58,1,36,15,8,22,93))

但是我得到了一个看起来像 wrong_df 的数据框

wrong_df<- data.frame(ITEM_GROUP = c("Fruit","Fruit","Fruit","Fruit","Fruit","Vegetable","Vegetable","Vegetable","Vegetable","Dairy","Dairy","Dairy","Dairy","Dairy"), 
                        ITEM_NAME = c("Apple","Banana","Orange","Mango","Papaya","Carrot","Potato","Brinjal","Raddish","Milk","Curd","Cheese","Milk","Paneer"),
                        Price = c(100,80,80,90,65,70,60,70,25,60,40,35,50,120),
                        percentile_rank=c(13,10,11,12,7,8,5,9,1,6,3,3,4,14))

这个问题是在我将 R 版本更新到 4.0.2 后才出现的

【问题讨论】：

标签： r percentile

【解决方案1】：

我认为这不是 R 问题，但似乎是 this open GitHub issue 中提到的 dplyr 1.0.0 的问题。查看从那里获取的两个函数的输出差异。

ntile_083(my_basket$Price,100)
#[1] 86 65 72 79 43 51 29 58  1 36 15  8 22 93
ntile_100(my_basket$Price,100)
#[1] 13 10 11 12  7  8  5  9  1  6  3  2  4 14

您现在可以使用ntile_083 获取以前的功能。

【讨论】：