TL;DR
您需要提供一个布尔向量来识别您尝试重新分配的数据框单元格。在您的情况下,将异常值和错误数据更改为平均值(估算)。
我会分几个步骤来做:
df = pd.DataFrame([0,1,3,'blah',4,5,'blah'], columns = ['pickup_latitude'])
# Identify the numeric observations
numeric = df['pickup_latitude'].astype(str).str.isdigit()
# Calculate mean
mean = df.loc[numeric,'pickup_latitude'].mean()
# Impute non numeric values
df.loc[~numeric,'pickup_latitude'] = mean
# Impute outliers
df.loc[df['pickup_latitude'] >= mean, 'pickup_latitude'] = mean
df['pickup_latitude']
Out[81]:
0 0
1 1
2 2.6
3 2.6
4 2.6
5 2.6
6 2.6
Name: pickup_latitude, dtype: object
我也会深入研究清理数据。
直观解释:
我认为它不会因为数字数据中的时间戳等数据完整性问题而无法估算。我能够复制您描述的第一个错误。
你不能这样做:
import pandas as pd
df = pd.DataFrame([0,1,3,4,5], columns = ['pickup_latitude'])
if df['pickup_latitude'] >= df['pickup_latitude'].mean():
df['pickup_latitude'] = df['pickup_latitude'].mean()
代码尝试将一个系列与一个常数进行比较:
df['pickup_latitude']
Out[12]:
0 0
1 1
2 3
3 4
4 5
Name: pickup_latitude, dtype: int64
df['pickup_latitude'].mean()
Out[13]: 2.6
if df['pickup_latitude'] >= df['pickup_latitude'].mean():
df['pickup_latitude'] = df['pickup_latitude'].mean()
Traceback (most recent call last):
File "<ipython-input-15-1135c8386dd6>", line 1, in <module>
if df['pickup_latitude'] >= df['pickup_latitude'].mean():
File "C:\Users\____\AppData\Local\Continuum\anaconda3\envs\DS\lib\site-packages\pandas\core\generic.py", line 1121, in __nonzero__
.format(self.__class__.__name__))
ValueError: The truth value of a Series is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all().
第二个错误是您的数据特有的。我会调查为什么不同的数据类型驻留在同一列(数字和时间戳)。