Python：用列表中的多个单词替换列中的多个单词并将它们写入 Pandas 中的不同列

Question

我有一个数据框和一个列表如下：

data = {{"text":["I have one apple and two bananas", "this is my apple", "she has three apples","My friend has five apples but she only has one banana"]}
df= pd.DataFrame(data=data, columns=['text'])

my_list = ['one','two','three','four','five']

我想要输出的是一个额外的列“new_text”，其中包含列表中单词的句子被替换为 my_list 中的每个单词，因此输出如下所示：

output:

  text                               new_text
0 I have one apple and two bananas   I have two apple and three bananas, I have three apple and four bananas,I have four apple and five bananas,I have five apple and one bananas,...
1 this is my apple                   this is my apple
2 she has three apples               she has two apples,she has four apples,she has five apples,...

and so on...

同句和复数的重复无关紧要，唯一重要的是列表中的所有单词都出现在'new_text'列的句子中

我已经尝试过这里的代码：Python: Replace one word in a sentence with a list of words and put thenew sentences in another column in pandas

第 1 步有一个例外，但它只找到第一个单词：

 data1 = data['text'].str.extract(
r"(?i)(?P<before>.*)\s(?P<clock>\(?=\bone\b | \btwo\b | \bthree\b | \bfour\b | \bfive\b))\s(?P<after>.*)")

提前谢谢你

Answer 1

你可以用这个：

a = ["I have one apple and two bananas", "this is my apple",
     "she has three apples", "My friend has five apples but she only has one banana"]

b = ['one','two','three','four','five', 'six']

new = []
for sentence in a:
    newSen = []

    for word in sentence.split():
        if word in b:
             newSen.append(b[b.index(word) + 1])
        else:
            newSen.append(word)

    new.append(' '.join(newSen))

print(new) #output : ['I have two apple and three bananas', 'this is my apple', 'she has four apples', 'My friend has six apples but she only has two banana']