【发布时间】:2019-11-04 23:22:15
【问题描述】:
我的大学服务器上托管了一个 php 文件,当我在服务器上运行此文件时,它运行良好。运行链接http://www.alkadhum-col.edu.iq/Teachers%20Activities/get.php 中的php 文件后,我可以获取json 数据,但是当我在应用程序屏幕上颤振尝试时无法获取。
首先,我尝试更改网址不起作用。其次,我试图将 json 对象转换为 .toString() 并且也不起作用。
import 'package:flutter/material.dart';
import 'package:http/http.dart' show get;
import 'dart:convert';
class Post {
String name;
String msg;
String day;
String date;
Post({this.name, this.msg, this.day, this.date});
factory Post.fromJson(Map<String, dynamic> json) {
return Post(
name: json['name'].toString(),
msg: json['msg'].toString(),
day: json['day'].toString(),
date: json['date'].toString(),
);
}
}
class CustomListView extends StatelessWidget {
List teachers = [];
CustomListView(this.teachers);
@override
Widget build(BuildContext context) {
return (
ListView.builder(
itemCount: teachers.length,
itemBuilder: (BuildContext context, int index) {
return createviewItem(teachers[index], context);
},
)
);
}
Widget createviewItem(Post teachers, BuildContext context) {
return ListTile(
title: new Card(
child: new Container(
decoration: BoxDecoration(border: Border.all(color: Colors.lightBlue)),
padding: EdgeInsets.all(20.0),
margin: EdgeInsets.all(20.0),
child: Column(children: <Widget>[
new Text(teachers.name),
new Text(teachers.msg),
new Text(teachers.day),
new Text(teachers.date)
],),
)
)
);
}
}
Future<List<Post>> downloadJSON() async {
final jsonEndpoint = "http://www.alkadhum-col.edu.iq/Teachers%20Activities/get.php";
final response = await get(jsonEndpoint);
if (response.statusCode == 200) {
List teachers = json.decode(response.body);
return teachers.map(
(teacher) => new Post.fromJson(teacher)
).toList();
}
else {
throw Exception("Unable to get JSON data");
}
}
class MyApp extends StatelessWidget {
@override
Widget build(BuildContext context) {
return new MaterialApp(
theme: new ThemeData(
primarySwatch: Colors.deepOrange,
),
home: new Scaffold(
appBar: new AppBar(title: const Text('Flutter and PHP')),
body: new Center(
child: new FutureBuilder<List<Post>>(
future: downloadJSON(),
builder: (context, snapshot) {
if (snapshot.hasData) {
List<Post> teachers = snapshot.data;
return new CustomListView(teachers);
} else if (snapshot.hasError) {
return Text('${snapshot.error}');
}
//return a circular progress indicator.
return new CircularProgressIndicator();
},
),
),
),
);
}
}
void main() {
runApp(MyApp());
}
我收到格式异常:意外字符(在字符 115 处)和一些数据出现在列表中,而不是字符串形式。
【问题讨论】:
-
不用数据模型也行
-
您正在使用您创建的名为 Post 的类对 json 数据进行建模
-
是的,但是如何让它工作
-
var data = jsonDecode(jsonData);打印(数据['someData']);
-
我已经这样做了。我的问题是如何在我的应用屏幕上打印它们?。