【发布时间】:2020-07-02 05:15:03
【问题描述】:
我在使用 Pipeline 和 GridSearchCV 查找平均误差 (MAE) 时面临挑战
背景:
我参与过一个数据科学项目(如下所示的 MWE),其中一个 MAE 值将作为分类器的性能指标返回。
#Library
import pandas as pd
from sklearn.ensemble import RandomForestClassifier
from sklearn.model_selection import train_test_split
from sklearn.metrics import mean_absolute_error
#Data import and preparation
data = pd.read_csv("data.csv")
data_features = ['location','event_type_count','log_feature_count','total_volume','resource_type_count','severity_type']
X = data[data_features]
y = data.fault_severity
#Train Validation Split for Cross Validation
X_train, X_valid, y_train, y_valid = train_test_split(X, y, train_size=0.8, test_size=0.2, random_state=0)
#RandomForest Modeling
RF_model = RandomForestClassifier(n_estimators=100, random_state=0)
RF_model.fit(X_train, y_train)
#RandomForest Prediction
y_predict = RF_model.predict(X_valid)
#MAE
print(mean_absolute_error(y_valid, y_predict))
#Output:
# 0.38727149627623564
挑战:
现在我正在尝试使用 Pipeline 和 GridSearchCV(如下所示的 MWE)来实现相同的功能。期望与上面返回的 MAE 值相同。不幸的是,我无法使用下面的 3 种方法来正确处理它。
#Library
import pandas as pd
from sklearn.ensemble import RandomForestClassifier
from sklearn.model_selection import train_test_split
from sklearn.pipeline import Pipeline
from sklearn.model_selection import GridSearchCV
#Data import and preparation
data = pd.read_csv("data.csv")
data_features = ['location','event_type_count','log_feature_count','total_volume','resource_type_count','severity_type']
X = data[data_features]
y = data.fault_severity
#Train Validation Split for Cross Validation
X_train, X_valid, y_train, y_valid = train_test_split(X, y, train_size=0.8, test_size=0.2, random_state=0)
#RandomForest Modeling via Pipeline and Hyper-parameter tuning
steps = [('rf', RandomForestClassifier(random_state=0))]
pipeline = Pipeline(steps) # define the pipeline object.
parameters = {'rf__n_estimators':[100]}
grid = GridSearchCV(pipeline, param_grid=parameters, scoring='neg_mean_squared_error', cv=None, refit=True)
grid.fit(X_train, y_train)
#Approach 1:
print(grid.best_score_)
# Output:
# -0.508130081300813
#Approach 2:
y_predict=grid.predict(X_valid)
print("score = %3.2f"%(grid.score(y_predict, y_valid)))
# Output:
# ValueError: Expected 2D array, got 1D array instead:
# array=[0. 0. 0. ... 0. 1. 0.].
# Reshape your data either using array.reshape(-1, 1) if your data has a single feature or array.reshape(1, -1) if it contains a single sample.
#Approach 3:
y_predict_df = pd.DataFrame(y_predict.reshape(len(y_predict), -1),columns=['fault_severity'])
print("score = %3.2f"%(grid.score(y_predict_df, y_valid)))
# Output:
# ValueError: Number of features of the model must match the input. Model n_features is 6 and input n_features is 1
讨论:
方法一:
如在GridSearchCV() 中,scoring 变量设置为neg_mean_squared_error,试图读取grid.best_score_。但它没有得到相同的 MAE 结果。
方法 2:
尝试使用grid.predict(X_valid) 获取y_predict 值。然后尝试使用grid.score(y_predict, y_valid) 获取MAE,因为GridSearchCV() 中的scoring 变量设置为neg_mean_squared_error。它返回了一个 ValueError 抱怨“预期的二维数组,而不是一维数组”。
方法 3:
试图重塑y_predict,它也没有工作。这次它返回“ValueError:模型的特征数必须与输入匹配。”
如果您能帮助指出我可能犯错误的地方会很有帮助?
如果您需要,data.csv 可在https://www.dropbox.com/s/t1h53jg1hy4x33b/data.csv 获得
非常感谢
【问题讨论】:
标签: python pandas machine-learning scikit-learn data-science