如何检查在插补过程中丢弃了哪些特征?
包含所有NaNs 的列将被丢弃。您可以在不通过fit 和transform 进程的情况下使用df.isnull().all() 进行检查。其中True,就是那些将被丢弃的“特征”。
不过,确切的答案是将verbose=1 添加到您的估算器中,如下所示:
imp = Imputer(verbose=1)
为了让这个示例更清楚地说明发生了什么,请向df 添加另一列,其中包含所有NaN。
df.insert(2, 'g', np.nan)
df 现在看起来像这样:
a b g c d e f
0 -1.284658 0.246541 NaN -1.120987 0.559911 -1.189870 NaN
1 0.773717 0.430597 NaN -0.004346 -1.292080 1.993266 NaN
2 1.418761 -0.004749 NaN -0.181932 -0.305756 -0.135870 NaN
3 0.418673 -0.376318 NaN -0.860783 0.074135 -1.034095 NaN
4 -0.019873 0.006210 NaN 0.364384 1.029895 -0.188727 NaN
5 0.903661 0.123575 NaN -0.556970 1.344985 -1.109806 NaN
6 -0.069168 -0.385597 NaN 0.684345 0.645920 1.159898 NaN
7 0.695782 0.030239 NaN -0.777304 -0.037102 2.053028 NaN
8 -0.256409 0.106735 NaN -0.729710 0.254626 1.064925 NaN
9 0.235507 -0.087767 NaN 0.626121 1.391286 0.449158 NaN
正在运行...
imp.fit(df)
imp.transform(df)
现在输出以下“详细”消息,告诉您删除了哪些列[2 6]:
Warning (from warnings module):
File "C:\Python34\lib\site-packages\sklearn\preprocessing\imputation.py", line 347
"observed values: %s" % missing)
UserWarning: Deleting features without observed values: [2 6]
array([[-1.284658, 0.246541, -1.120987, 0.559911, -1.18987 ],
[ 0.773717, 0.430597, -0.004346, -1.29208 , 1.993266],
[ 1.418761, -0.004749, -0.181932, -0.305756, -0.13587 ],
[ 0.418673, -0.376318, -0.860783, 0.074135, -1.034095],
[-0.019873, 0.00621 , 0.364384, 1.029895, -0.188727],
[ 0.903661, 0.123575, -0.55697 , 1.344985, -1.109806],
[-0.069168, -0.385597, 0.684345, 0.64592 , 1.159898],
[ 0.695782, 0.030239, -0.777304, -0.037102, 2.053028],
[-0.256409, 0.106735, -0.72971 , 0.254626, 1.064925],
[ 0.235507, -0.087767, 0.626121, 1.391286, 0.449158]])
插补后保留了哪些特征?
插补后剩余的列和值。
使用我以前的df,如果我们添加一些NaN:
df.loc[[1, 7, 3], ['a', 'c', 'e']] = np.nan
df 看起来像这样:
a b g c d e f
0 -1.284658 0.246541 NaN -1.120987 0.559911 -1.189870 NaN
1 NaN 0.430597 NaN NaN -1.292080 NaN NaN
2 1.418761 -0.004749 NaN -0.181932 -0.305756 -0.135870 NaN
3 NaN -0.376318 NaN NaN 0.074135 NaN NaN
4 -0.019873 0.006210 NaN 0.364384 1.029895 -0.188727 NaN
5 0.903661 0.123575 NaN -0.556970 1.344985 -1.109806 NaN
6 -0.069168 -0.385597 NaN 0.684345 0.645920 1.159898 NaN
7 NaN 0.030239 NaN NaN -0.037102 NaN NaN
8 -0.256409 0.106735 NaN -0.729710 0.254626 1.064925 NaN
9 0.235507 -0.087767 NaN 0.626121 1.391286 0.449158 NaN
重要的是要了解您所使用的估算策略。 Imputer 的默认值是 mean。这意味着它将用给定列的平均值替换 NaN 值。
为了证明,先检查每一列的均值:
>>> df.mean()
a 0.132546
b 0.008947
g NaN
c -0.130678
d 0.366582
e 0.007101
f NaN
dtype: float64
然后您可以进行拟合和转换,并查看转换后的插补数据中是否有任何值在 imp.statistics_ 超参数中。
imp = Imputer(verbose=1)
imp.fit(df)
imp.transform(df)
返回以下 - 再次,需要注意的关键是 NaN 值已替换为给定列的 mean。例如,无论您在第一列中何处看到 0.13254586,您都会注意到它们出现在第 1、3 和 7 行(之前为 NaNs):
Warning (from warnings module):
File "C:\Python34\lib\site-packages\sklearn\preprocessing\imputation.py", line 347
"observed values: %s" % missing)
UserWarning: Deleting features without observed values: [2 6]
array([[-1.284658 , 0.246541 , -1.120987 , 0.559911 , -1.18987 ],
[ 0.13254586, 0.430597 , -0.13067843, -1.29208 , 0.00710114],
[ 1.418761 , -0.004749 , -0.181932 , -0.305756 , -0.13587 ],
[ 0.13254586, -0.376318 , -0.13067843, 0.074135 , 0.00710114],
[-0.019873 , 0.00621 , 0.364384 , 1.029895 , -0.188727 ],
[ 0.903661 , 0.123575 , -0.55697 , 1.344985 , -1.109806 ],
[-0.069168 , -0.385597 , 0.684345 , 0.64592 , 1.159898 ],
[ 0.13254586, 0.030239 , -0.13067843, -0.037102 , 0.00710114],
[-0.256409 , 0.106735 , -0.72971 , 0.254626 , 1.064925 ],
[ 0.235507 , -0.087767 , 0.626121 , 1.391286 , 0.449158 ]])
如果您想进行布尔比较以查看估算的值,您可以执行以下操作(不是万无一失,但最可靠的方法):
np.reshape(np.in1d(imp.transform(df), imp.statistics_), imp.transform(df).shape)
array([[False, False, False, False, False],
[ True, False, True, False, True],
[False, False, False, False, False],
[ True, False, True, False, True],
[False, False, False, False, False],
[False, False, False, False, False],
[False, False, False, False, False],
[ True, False, True, False, True],
[False, False, False, False, False],
[False, False, False, False, False]], dtype=bool)