在熊猫数据框中查找时间变化答案

【问题标题】：Find change in time in a pandas data frame在熊猫数据框中查找时间变化
【发布时间】：2021-11-10 16:54:23
【问题描述】：

我从 Pandas 数据框中提取了以下列表。它基本上是一个开始日期和时间和一个结束日期和时间，我想找出它们之间的区别。

start_date  = ['29.12.2020', '29.12.2020', '30.12.2020', '30.12.2020', '30.12.2020']    
start_time = [datetime.time(11, 10), datetime.time(23, 15), datetime.time(5, 15), datetime.time(11, 15), datetime.time(17, 15)]

end_date = ['29.12.2020', '30.12.2020', '30.12.2020', '30.12.2020', '30.12.2020']
end_time = [datetime.time(23, 15), datetime.time(5, 15), datetime.time(11, 15), datetime.time(17, 15), datetime.time(23, 15)]

所以，我想加入日期和时间以有一个起点和一个终点，并以 HH:MM 格式找出这两者之间的差异。

比如我们取第一行，两个时间点的差应该是12:05（12小时5分钟）

【问题讨论】：

标签： python pandas dataframe datetime timedelta

【解决方案1】：

你可以试试这个。

import datetime

start_date  = ['29.12.2020', '29.12.2020', '30.12.2020', '30.12.2020', '30.12.2020']

start_time = [datetime.time(11, 10), datetime.time(23, 15), datetime.time(5, 15), datetime.time(11, 15), datetime.time(17, 15)]

end_date = ['29.12.2020', '30.12.2020', '30.12.2020', '30.12.2020', '30.12.2020']
end_time = [datetime.time(23, 15), datetime.time(5, 15), datetime.time(11, 15), datetime.time(17, 15), datetime.time(23, 15)]


for start_d, start_t, end_d, end_t in zip(start_date, start_time,end_date, end_time):
    
    start_date_time = datetime.datetime.strptime(start_d, '%d.%m.%Y')
    start_date_time = start_date_time.replace(hour=start_t.hour, minute=start_t.minute)
        
    end_date_time = datetime.datetime.strptime(end_d, '%d.%m.%Y')
    end_date_time = end_date_time.replace(hour=end_t.hour, minute=end_t.minute)
    
    time_diff = end_date_time - start_date_time
    diff_str = f"{time_diff.days}days {time_diff.seconds//3600}hours {(time_diff.seconds//60)%60}minutes "
    print(diff_str)

【讨论】：

【解决方案2】：

start_date  = ['29.12.2020', '29.12.2020', '30.12.2020', '30.12.2020', '30.12.2020']
start_time = [datetime.time(11, 10), datetime.time(23, 15), datetime.time(5, 15), datetime.time(11, 15), datetime.time(17, 15)]
end_date = ['29.12.2020', '30.12.2020', '30.12.2020', '30.12.2020', '30.12.2020']
end_time = [datetime.time(23, 15), datetime.time(5, 15), datetime.time(11, 15), datetime.time(17, 15), datetime.time(23, 15)]

df = pd.DataFrame(data={'start_date': start_date,
                        'start_time': start_time,
                        'end_date': end_date,
                        'end_time': end_time})

df['start_date_time'] = pd.to_datetime(df['start_date'] + ' ' + df['start_time'].astype(str))
df['end_date_time'] = pd.to_datetime(df['end_date'] + ' ' + df['end_time'].astype(str))

df['diff'] = (df['end_date_time'] - df['start_date_time'])
df['hours'] = df['diff']/ np.timedelta64(1, 'h')
df['HH:MM'] = df['hours'].astype(int).astype(str) + ':' + ((df['diff']/ np.timedelta64(1, 'm')) - (df['hours'].astype(int)*60)).astype(int).astype(str)
print(df[['start_date_time', 'end_date_time', 'HH:MM']])

输出：

      start_date_time       end_date_time HH:MM
0 2020-12-29 11:10:00 2020-12-29 23:15:00  12:5
1 2020-12-29 23:15:00 2020-12-30 05:15:00   6:0
2 2020-12-30 05:15:00 2020-12-30 11:15:00   6:0
3 2020-12-30 11:15:00 2020-12-30 17:15:00   6:0
4 2020-12-30 17:15:00 2020-12-30 23:15:00   6:0

【讨论】：