【问题标题】:Flutter WebView exception on device back button pressed按下设备后退按钮上的 Flutter WebView 异常
【发布时间】:2020-08-03 10:13:11
【问题描述】:

我对 Flutter 很陌生,所以如果这是一个基本问题,请原谅我。

我正在尝试创建一个仅显示全屏 web 视图的 Flutter 应用程序,但我需要设备返回按钮才能返回历史记录。第一项任务我很轻松地完成了,但第二项任务却是一场斗争。

我按照answer 中的说明进行操作,但我无法消除仅按后退按钮的 360 多行答案的所有混乱并使其正常工作。

我的代码很简单:

import 'dart:io';
import 'package:flutter/material.dart';
import 'package:flutter/services.dart';
import 'package:webview_flutter/webview_flutter.dart';

void main() => runApp(MyApp());

WebViewController _controller;

Future<void> _onWillPop(BuildContext context) async {
  if (await _controller.canGoBack()) {
    _controller.goBack();
  } else {
    exit(0);
    return Future.value(false);
  }
}

class MyApp extends StatelessWidget {
  @override
  Widget build(BuildContext context) {
    SystemChrome.setEnabledSystemUIOverlays([]);
    return WillPopScope(
      onWillPop: () => _onWillPop(context),
      child: MaterialApp(title: 'Test App', home: WebView(
      initialUrl: 'https://google.com',
      javascriptMode: JavascriptMode.unrestricted,
      onWebViewCreated: (WebViewController c) => _controller = c,
    )),
    );
  }
}

但是当我尝试按下设备返回按钮时,它会抛出以下错误:

java.lang.RuntimeException: Cannot execute operation because FlutterJNI is not attached to native.
    at io.flutter.embedding.engine.FlutterJNI.ensureAttachedToNative(FlutterJNI.java:227)
    at io.flutter.embedding.engine.FlutterJNI.markTextureFrameAvailable(FlutterJNI.java:554)
    at io.flutter.embedding.engine.renderer.FlutterRenderer.markTextureFrameAvailable(FlutterRenderer.java:274)
    at io.flutter.embedding.engine.renderer.FlutterRenderer.access$300(FlutterRenderer.java:38)
    at io.flutter.embedding.engine.renderer.FlutterRenderer$SurfaceTextureRegistryEntry$1.onFrameAvailable(FlutterRenderer.java:145)
    at android.graphics.SurfaceTexture$1.handleMessage(SurfaceTexture.java:211)
    at android.os.Handler.dispatchMessage(Handler.java:107)
    at android.os.Looper.loop(Looper.java:224)
    at android.app.ActivityThread.main(ActivityThread.java:7520)
    at java.lang.reflect.Method.invoke(Native Method)
    at com.android.internal.os.RuntimeInit$MethodAndArgsCaller.run(RuntimeInit.java:539)
    at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:950)

flutter 的 github 上至少有 3 个线程,但没有一个解决方案对我有用。我在这里错过了什么?

【问题讨论】:

  • 我认为这是因为您没有使用 Completer
  • 是的,但我似乎也需要一个有状态的小部件。

标签: android ios flutter webview flutterwebviewplugin


【解决方案1】:

您可以在下面复制粘贴运行完整代码
您可以使用Completer
代码 sn -p

WebViewController controller;

final Completer<WebViewController> _controllerCompleter =
          Completer<WebViewController>();
...
onWebViewCreated: (WebViewController c) {
                _controllerCompleter.future.then((value) => controller = value);
                _controllerCompleter.complete(c);
              },

工作演示

完整代码

import 'dart:io';
import 'package:flutter/material.dart';
import 'package:flutter/services.dart';
import 'package:webview_flutter/webview_flutter.dart';
import 'dart:async';

void main() {
  runApp(MyApp());
}

class MyApp extends StatelessWidget {
  @override
  Widget build(BuildContext context) {
    return MaterialApp(
      title: 'Flutter Demo',
      theme: ThemeData(
        primarySwatch: Colors.blue,
        visualDensity: VisualDensity.adaptivePlatformDensity,
      ),
      home: MyHomePage(title: 'Flutter Demo Home Page'),
    );
  }
}

class MyHomePage extends StatefulWidget {
  MyHomePage({Key key, this.title}) : super(key: key);

  final String title;

  @override
  _MyHomePageState createState() => _MyHomePageState();
}

class _MyHomePageState extends State<MyHomePage> {
  WebViewController controller;

  final Completer<WebViewController> _controllerCompleter =
      Completer<WebViewController>();

  Future<void> _onWillPop(BuildContext context) async {
    print("onwillpop");
    if (await controller.canGoBack()) {
      controller.goBack();
    } else {
      exit(0);
      return Future.value(false);
    }
  }

  @override
  Widget build(BuildContext context) {
    return WillPopScope(
      onWillPop: () => _onWillPop(context),
      child: Scaffold(
        body: WebView(
          initialUrl: 'https://flutter.dev/',
          javascriptMode: JavascriptMode.unrestricted,
          onWebViewCreated: (WebViewController c) {
            _controllerCompleter.future.then((value) => controller = value);
            _controllerCompleter.complete(c);
          },
        ),
      ),
    );
  }
}

【讨论】:

  • 很高兴为您提供帮助。如果对您有帮助,请将其标记为答案。谢谢。
【解决方案2】:

在 Android MainActivity.kt 中,只需添加以下内容:

override fun onDestroy() { flutterEngine?.platformViewsController?.onFlutterViewDestroyed() super.onDestroy() }

【讨论】:

    【解决方案3】:

    这是可行的解决方案(100% 工作)-

      // Use any webview plugin
      // WebView _controller;
    
      Future<void> _handleBack(context) async {
        var status = await _controller.canGoBack();
        if (status) {
          _controller.goBack();
        } else {
          showDialog(
              context: context,
              builder: (context) => AlertDialog(
                    title: Text('Do you want to exit'),
                    actions: <Widget>[
                      FlatButton(
                        onPressed: () {
                          Navigator.of(context).pop();
                        },
                        child: Text('No'),
                      ),
                      FlatButton(
                        onPressed: () {
                          SystemNavigator.pop();
                        },
                        child: Text('Yes'),
                      ),
                    ],
                  ));
        }
      }
    

    这里是调用 WillPopScope

      @override
      Widget build(BuildContext context) {
        return WillPopScope(
                onWillPop: () => _handleBack(context),
                child: SafeArea(
                  top: true,
                  child: Scaffold(......)))
    

    【讨论】:

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