在word文档中获取表格形状的数据框

Question

我正在阅读一个 excel 文件，提取一个特定的 df 并将其放入 word 文档中。我面临的问题是：

1. DF 一旦添加到 para.变得完全没用。

完整的代码写在下面。

#importing required libraries
import pandas as pd
import numpy as np
eod = pd.read_excel('df.xlsx')
import datetime
import docx 
from datetime import date
legal = docx.Document('legal.docx')

#Calculating No. days from SCN
eod['SCN Days'] = (pd.Timestamp('now').floor('d') - eod['SCN Date']).dt.days

#Generation list of EFE for Final Showcause Notice to be issued today
FSCN_today = eod.where(eod['SCN Days']>20)
#Dropping Null from generated list
FSCN_today = FSCN_today.dropna(how ="all")
FSCN_today = FSCN_today[['Exporter Name','EFE','DESTINATION','VALUE']]

#Getting Unique Values in the list generated
s_values = FSCN_today['Exporter Name'].unique()

#Iterating through List
for c in s_values:
    df1 = FSCN_today[FSCN_today['Exporter Name'] == c]
    legal.paragraphs[7].text = c
    legal.paragraphs[8].text = df1.iloc[10:1]
    legal.paragraphs[15].text = str(df1)
    notice_name = str(c)+ ".docx"
    legal.save(notice_name)

#Update Date & Status of FSCN Issued today
eod['FSCN Date'] = np.where((eod['Status']=="SCN ISSUED") & (eod['SCN Days']>20),date.today(),eod['FSCN Date'])
eod['Status'] = np.where((eod['Status']=="SCN ISSUED") & (eod['SCN Days']>20),"FSCN ISSUED",eod['Status'])

#In progress
name = "EOD "+ str(date.today())+ ".xlsx"
#eod.to_excel(name,index =False)  

以下行有错误。

legal.paragraphs[15].text = str(df1)

Answer 1

您可以通过创建一个表来完成这项工作，将数据框传输到该表(as explained in this post)，然后将该表放在 legal.paragraphs[15] 所在的位置：

#importing required libraries
import pandas as pd
import numpy as np
eod = pd.read_excel('df.xlsx')
import datetime
import docx 
from datetime import date

#Calculating No. days from SCN
eod['SCN Days'] = (pd.Timestamp('now').floor('d') - eod['SCN Date']).dt.days

#Generation list of EFE for Final Showcause Notice to be issued today
FSCN_today = eod.where(eod['SCN Days']>20)
#Dropping Null from generated list
FSCN_today = FSCN_today.dropna(how ="all")
FSCN_today = FSCN_today[['Exporter Name','EFE','DESTINATION','VALUE']]

#Getting Unique Values in the list generated
s_values = FSCN_today['Exporter Name'].unique()

#Iterating through List
for c in s_values:
    legal = docx.Document('legal.docx')
    df1 = FSCN_today[FSCN_today['Exporter Name'] == c]
    legal.paragraphs[7].text = c
    legal.paragraphs[8].text = df1.iloc[10:1].iloc
    legal.paragraphs[15].text = ""
    t = legal.add_table(df1.shape[0]+1, df1.shape[1])
    for j in range(df1.shape[-1]):
        t.cell(0,j).text = df1.columns[j]
    for i in range(df1.shape[0]):
        for j in range(df1.shape[-1]):
            t.cell(i+1,j).text = str(df1.values[i,j])    
    legal.paragraphs[15]._p.addnext(t._tbl)
    notice_name = str(c)+ ".docx"
    legal.save(notice_name)

#Update Date & Status of FSCN Issued today
eod['FSCN Date'] = np.where((eod['Status']=="SCN ISSUED") & (eod['SCN Days']>20),date.today(),eod['FSCN Date'])
eod['Status'] = np.where((eod['Status']=="SCN ISSUED") & (eod['SCN Days']>20),"FSCN ISSUED",eod['Status'])

#In progress
name = "EOD "+ str(date.today())+ ".xlsx"
#eod.to_excel(name,index =False) 

（我将 legal = docx.Document('legal.docx') 移动到循环中，因为连续的 docx 保留了较旧的导出器值）

Answer 2

我从未与python-docx 合作过，所以我很确定我的尝试并不理想。以下确实适用于示例数据。

本质上，我在文档中添加了一个表格，并将 DataFrame 的列标签和内容插入到表格中。有一些令人讨厌的部分是我无法解决的（我访问paragraph 和table 的_ 属性的部分）。

我替换了上面代码的以下部分

#Iterating through List
for c in s_values:
    df1 = FSCN_today[FSCN_today['Exporter Name'] == c]
    legal.paragraphs[7].text = c
    legal.paragraphs[8].text = df1.iloc[10:1]
    legal.paragraphs[15].text = str(df1)
    notice_name = str(c)+ ".docx"
    legal.save(notice_name)

用这个（cmets 用于突出我所做的，换行以提高可读性）：

for c in s_values:
    df1 = FSCN_today[FSCN_today['Exporter Name'] == c]
    legal.paragraphs[7].text = c
    legal.paragraphs[8].text = df1[10:1].iloc # <- Changed

    # Add a table with the same amount of columns as the DataFrame
    table = legal.add_table(0, len(df1.columns))
    table.autofit = True

    # Create the header line (= column labels of the DataFrame)
    header = table.add_row()
    for col, cell in enumerate(header.cells):
        cell.text = str(df1.columns[col])

    # Insert the content of DataFrame in the table
    for ind in df1.index:
        row = table.add_row()
        for pos, col in enumerate(df1.columns):
            row.cells[pos].text = df1.loc[ind, col]

    # Add a break in paragraph 15 (before the table)
    legal.paragraphs[15].add_run().add_break()

    # Add the table to paragraph 15
    legal.paragraphs[15]._p.addnext(table._tbl)

    notice_name = str(c)+ ".docx"
    legal.save(notice_name)

    # Remove the table
    table._element.getparent().remove(table._element)

Answer 3

我注意到legal.paragraphs[8].text = df1.iloc[10:1] 看起来很奇怪。

如果您将其更改为 legal.paragraphs[8].text = df1[10:1].iloc，则生成的 .docx 文件对我来说看起来更合理。

我不知道您想要的输出是什么，所以这是我对所呈现内容的最佳猜测。