计算重复少于 2 次的每个名称和删除名称的数量 [重复]答案

【问题标题】：count the number of each name and drop names that are repeated less than 2 times [duplicate]计算重复少于 2 次的每个名称和删除名称的数量 [重复]
【发布时间】：2021-05-05 16:43:48
【问题描述】：

在这个数据集中

data = pd.DataFrame({'name':["a","c","d","b","a","b","c","a","c","d","b","n",
                         "m""b","b","c","a","c","d","b","a","b","b","b","c",
                         "a","c","d","b","a","b","b","b","c","a","c","d","b","a","b","b","b","c"]})

我想统计每个名字的个数，以及重复少于 2 次的名字。

【问题讨论】：

这是一个可能的解决方案stackoverflow.com/questions/49735683/…

标签： python pandas count unique

【解决方案1】：

一种方法是使用过滤器：

data.groupby('name').filter(lambda x : len(x)>1)

【讨论】：

你的意思可能是：data.groupby('name').filter(lambda x : len(x)>1)
感谢@BaruchG。你说的对！我会编辑它。

【解决方案2】：

您可以使用map和value_counts函数如下：

   only_duplicates = data[data['name'].map(data['name'].value_counts()) > 1]

【讨论】：