【发布时间】：2015-11-18 11:59:54
【问题描述】：
我想更改 elasticsearch 中的评分系统，以摆脱计算一个术语的多次出现。例如，我想要：
“德州德州”
和
“德克萨斯”
以相同的分数出来。我发现 elasticsearch 所说的这种映射会禁用词频计数，但我的搜索结果并不相同：
"mappings":{
"business": {
"properties" : {
"name" : {
"type" : "string",
"index_options" : "docs",
"norms" : { "enabled": false}}
}
}
}
}
任何帮助将不胜感激，我无法找到很多这方面的信息。
编辑：
我正在添加我的搜索代码以及使用说明时返回的内容。
我的搜索码：
Settings settings = ImmutableSettings.settingsBuilder().put("cluster.name", "escluster").build();
Client client = new TransportClient(settings)
.addTransportAddress(new InetSocketTransportAddress("127.0.0.1", 9300));
SearchRequest request = Requests.searchRequest("businesses")
.source(SearchSourceBuilder.searchSource().query(QueryBuilders.boolQuery()
.should(QueryBuilders.matchQuery("name", "Texas")
.minimumShouldMatch("1")))).searchType(SearchType.DFS_QUERY_THEN_FETCH);
ExplainRequest request2 = client.prepareIndex("businesses", "business")
当我用解释搜索时，我得到：
"took" : 14,
"timed_out" : false,
"_shards" : {
"total" : 3,
"successful" : 3,
"failed" : 0
},
"hits" : {
"total" : 2,
"max_score" : 1.0,
"hits" : [ {
"_shard" : 1,
"_node" : "BTqBPVDET5Kr83r-CYPqfA",
"_index" : "businesses",
"_type" : "business",
"_id" : "AU9U5KBks4zEorv9YI4n",
"_score" : 1.0,
"_source":{
"name" : "texas"
}
,
"_explanation" : {
"value" : 1.0,
"description" : "weight(_all:texas in 0) [PerFieldSimilarity], result of:",
"details" : [ {
"value" : 1.0,
"description" : "fieldWeight in 0, product of:",
"details" : [ {
"value" : 1.0,
"description" : "tf(freq=1.0), with freq of:",
"details" : [ {
"value" : 1.0,
"description" : "termFreq=1.0"
} ]
}, {
"value" : 1.0,
"description" : "idf(docFreq=2, maxDocs=3)"
}, {
"value" : 1.0,
"description" : "fieldNorm(doc=0)"
} ]
} ]
}
}, {
"_shard" : 1,
"_node" : "BTqBPVDET5Kr83r-CYPqfA",
"_index" : "businesses",
"_type" : "business",
"_id" : "AU9U5K6Ks4zEorv9YI4o",
"_score" : 0.8660254,
"_source":{
"name" : "texas texas texas"
}
,
"_explanation" : {
"value" : 0.8660254,
"description" : "weight(_all:texas in 0) [PerFieldSimilarity], result of:",
"details" : [ {
"value" : 0.8660254,
"description" : "fieldWeight in 0, product of:",
"details" : [ {
"value" : 1.7320508,
"description" : "tf(freq=3.0), with freq of:",
"details" : [ {
"value" : 3.0,
"description" : "termFreq=3.0"
} ]
}, {
"value" : 1.0,
"description" : "idf(docFreq=2, maxDocs=3)"
}, {
"value" : 0.5,
"description" : "fieldNorm(doc=0)"
} ]
} ]
}
} ]
}
看起来它仍在考虑频率和文档频率。有任何想法吗？很抱歉格式不好，我不知道为什么它看起来如此怪诞。
编辑编辑：
我的代码来自浏览器搜索http://localhost:9200/businesses/business/_search?pretty=true&qname=texas 是：
{
"took" : 2,
"timed_out" : false,
"_shards" : {
"total" : 3,
"successful" : 3,
"failed" : 0
},
"hits" : {
"total" : 4,
"max_score" : 1.0,
"hits" : [ {
"_index" : "businesses",
"_type" : "business",
"_id" : "AU9YcCKjKvtg8NgyozGK",
"_score" : 1.0,
"_source":{"business" : {
"name" : "texas texas texas texas" }
}
}, {
"_index" : "businesses",
"_type" : "business",
"_id" : "AU9YateBKvtg8Ngyoy-p",
"_score" : 1.0,
"_source":{
"name" : "texas" }
}, {
"_index" : "businesses",
"_type" : "business",
"_id" : "AU9YavVnKvtg8Ngyoy-4",
"_score" : 1.0,
"_source":{
"name" : "texas texas texas" }
}, {
"_index" : "businesses",
"_type" : "business",
"_id" : "AU9Yb7NgKvtg8NgyozFf",
"_score" : 1.0,
"_source":{"business" : {
"name" : "texas texas texas" }
}
} ]
}
}
它会找到我在其中的所有 4 个对象，并且它们的分数都相同。 当我使用解释运行我的 java API 搜索时，我得到：
{
"took" : 2,
"timed_out" : false,
"_shards" : {
"total" : 3,
"successful" : 3,
"failed" : 0
},
"hits" : {
"total" : 2,
"max_score" : 1.287682,
"hits" : [ {
"_shard" : 1,
"_node" : "BTqBPVDET5Kr83r-CYPqfA",
"_index" : "businesses",
"_type" : "business",
"_id" : "AU9YateBKvtg8Ngyoy-p",
"_score" : 1.287682,
"_source":{
"name" : "texas" }
,
"_explanation" : {
"value" : 1.287682,
"description" : "weight(name:texas in 0) [PerFieldSimilarity], result of:",
"details" : [ {
"value" : 1.287682,
"description" : "fieldWeight in 0, product of:",
"details" : [ {
"value" : 1.0,
"description" : "tf(freq=1.0), with freq of:",
"details" : [ {
"value" : 1.0,
"description" : "termFreq=1.0"
} ]
}, {
"value" : 1.287682,
"description" : "idf(docFreq=2, maxDocs=4)"
}, {
"value" : 1.0,
"description" : "fieldNorm(doc=0)"
} ]
} ]
}
}, {
"_shard" : 1,
"_node" : "BTqBPVDET5Kr83r-CYPqfA",
"_index" : "businesses",
"_type" : "business",
"_id" : "AU9YavVnKvtg8Ngyoy-4",
"_score" : 1.1151654,
"_source":{
"name" : "texas texas texas" }
,
"_explanation" : {
"value" : 1.1151654,
"description" : "weight(name:texas in 0) [PerFieldSimilarity], result of:",
"details" : [ {
"value" : 1.1151654,
"description" : "fieldWeight in 0, product of:",
"details" : [ {
"value" : 1.7320508,
"description" : "tf(freq=3.0), with freq of:",
"details" : [ {
"value" : 3.0,
"description" : "termFreq=3.0"
} ]
}, {
"value" : 1.287682,
"description" : "idf(docFreq=2, maxDocs=4)"
}, {
"value" : 0.5,
"description" : "fieldNorm(doc=0)"
} ]
} ]
}
} ]
}
}
【问题讨论】：
-
不匹配可能更多地与
doc frequency而不是term frequency是否使用 search_type=dfs_query_then_fetch 。如果这无济于事，请尝试在查询中设置explain=true以查看得分细目 -
我将它切换到 dfs_query_then_fetch 但这不起作用。我将在稍后发布我的代码并解释结果
-
您也可以发布查询吗？
-
对不起，什么意思？我只是从上面执行 SearchRequest：ActionFuture af = client.search(request);
-
感谢您的格式编辑！
标签： elasticsearch frequency java term scoring