动态显示名字和姓氏作为选择选项答案

【问题标题】：Dynamically Displaying both First Name and Last Name as Select Options动态显示名字和姓氏作为选择选项
【发布时间】：2018-11-26 22:36:34
【问题描述】：

我正在尝试动态显示数据库中人员的名字和姓氏。我已经成功地显示了名字，但我不确定如何使用姓氏来做到这一点。任何帮助将不胜感激:)

PHP：

$swimmername_query = "SELECT * From Swimmers ORDER BY FirstName ASC";
$swimmername_results = mysqli_query($dbcon, $swimmername_query);
echo "<option value=>";
echo "Select Customer";
echo "</option>";

while ($displayname = mysqli_fetch_assoc($swimmername_results)){
echo "<option value = '".$displayname['FirstName']."'>".$displayname['FirstName']."</option>";
            }

【问题讨论】：

你的预期输出是什么？
让它成为“名字姓氏”。目前它只打印“FirstName”

标签： php sql select dynamic option

【解决方案1】：

您可以像这样直接在查询中连接它：

$swimmername_query = "SELECT *, CONCAT(FirstName, '-', LastName) AS FullName From Swimmers ORDER BY FirstName ASC";
$swimmername_results = mysqli_query($dbcon, $swimmername_query);
echo "<option value=>";
echo "Select Customer";
echo "</option>";

while ($displayname = mysqli_fetch_assoc($swimmername_results)){
     echo "<option value = '".$displayname['FullName']."'>".$displayname['FullName']."</option>";
}

或者在while循环中连接字符串：

$swimmername_query = "SELECT * From Swimmers ORDER BY FirstName ASC";
$swimmername_results = mysqli_query($dbcon, $swimmername_query);
echo "<option value=>";
echo "Select Customer";
echo "</option>";

while ($displayname = mysqli_fetch_assoc($swimmername_results)){
    $fullname = $displayname['FirstName']."-".$displayname['LastName'];
    echo "<option value = '".$fullname."'>".$fullname."</option>";
}

【讨论】：

【解决方案2】：

最好在查询中将 ID 列作为值并将名字与姓氏合并在一起。

$swimmername_query = "SELECT SwimmersID, Firstname || ' ' || Lastname SwimmerName From Swimmers ORDER BY FirstName ASC";
$swimmername_results = mysqli_query($dbcon, $swimmername_query);
echo "<option value=>";
echo "Select Customer";
echo "</option>";

while ($displayname = mysqli_fetch_assoc($swimmername_results)){
echo "<option value = '".$displayname['SwimmersID']."'>".$displayname['SwimmerName']."</option>";

【讨论】：