基本解决方案(对于这类事情更严格)
df <- data.frame(X1=c(a=1L,b=2L),
X2=c(a=0L,b=2L),
X3=c(a=1L,b=1L),
X4=c(a=1L,b=1L),
X5=c(a=1L,b=1L),
X6=c(a=1L,b=1L),
X7=c(a=1L,b=1L))
cn <- colnames(df)
cond <- as.integer(substr(cn,2L,nchar(cn))) %% 2L == 0L
colnames(df)[cond] <- paste0(cn[cond],"_is_pair")
一个 tidyverse 解决方案(由于 tidyeval 有点尴尬)
library(dplyr)
library(stringr)
library(tidyselect)
df <- data.frame(X1=c(a=1L,b=2L),
X2=c(a=0L,b=2L),
X3=c(a=1L,b=1L),
X4=c(a=1L,b=1L),
X5=c(a=1L,b=1L),
X6=c(a=1L,b=1L),
X7=c(a=1L,b=1L))
is_pair <- function(vars = peek_vars(fn = "is_pair")) {
vars[as.integer(str_sub(vars,2L,nchar(vars))) %% 2L == 0L]
}
df %>% rename_with(~paste0(.x,"_is_pair"),
is_pair())