如果 URL 被点击，文件名必须更改，我该怎么做？

Question

我在 HTML 文件中有这个 sn-p。但是我希望文件名从 1unread.txt 打开到 1read.txt 时会被更改，这样它就会进入读取列表。

<h2>Unread</h2>
<?php 
foreach (glob("*1unread.txt") as $filename) {
    echo "<a href='$filename'>Download {$filename}</a><br>" . "\n" ;
}
?>
<h2>Read</h2>
<?php 
foreach (glob("*1read.txt") as $filename) {
    echo "<a href='$filename'>Download {$filename}</a><br>" . "\n" ;
}
?>

如果在php.net 上阅读过，我可以用这个来更改文件名：

bool rename ( string $oldname , string $newname [, resource $context ] )

但是当使用下载链接时，我该如何实现呢？变量$context 有什么作用？我对 PHP 有点陌生，所以不要期望我能理解太多：P

还是谢谢

Answer 1

下载.php：

<?php
    //Only offer file to download which are having "unread" or "read" in their filename.
    if(!strstr($_GET['file'], 'unread') || !strstr($_GET['file'], 'read']))
        die('Invalid file.');

    //Make sure the file exists.
    if(!file_exists($_GET['file']))
        die('File not found.');

    echo file_get_contents($_GET['file']);

    if(strstr($_GET['file'], 'unread')) {
        //rename 1unread.txt to 1read.txt
        $newFileName = str_replace('unread', 'read', $_GET['file']);
        rename($_GET['file'], $newFileName);
        echo sprintf("RENAMED '%s' TO '%s'!", $_GET['file'], $newFileName); //Debug
    } else {
        //rename 1read.txt to 1unread.txt
        $newFileName = str_replace('read', 'unread', $_GET['file']);
        rename($_GET['file'], $newFileName);
        echo sprintf("RENAMED '%s' TO '%s'!", $_GET['file'], $newFileName); //Debug
    }
?>

用这个替换下载按钮：

echo "<a href='download.php?file=$filename'>Download {$filename}</a><br>" . "\n" ;