Python脚本，将索引项替换为索引项

Question

我正在尝试创建一个 python 脚本。

我有两个列表。

如果列表中的项目1

==[]（空列表） 要么 =="Pxxx-xx"

那么它必须替换为第二个列表中相同索引的项目。

所以：

list1 =["P324-12","P321-01","Pxxx-xx",[],"P134-23"]

list2 =["A00","A01","A02","A03","A04"]

那么输出应该是：

out=["P324-12","P321-01","A02","A03","P134-23"]

现在我得到了这个工作：

list1 = IN[0]
replacement = IN[1]
out = []

for itm in list1:
    if itm == [] or itm == "Pxxx-xx":
        out.append(replacement)
    else:
        out.append(itm)
#Assign your output to the OUT variable.
OUT = out

但这只会用单个项目替换它，而不是替换列表中的项目。

现在我试过了：

list1 = IN[0]
list2 = IN[1]
out = []

for idx, itm in enumerate(list1):
    if itm == [] or itm == "Pxxx-xx":
        out.append(list2[idx])
    else:
        out.append(itm)
#Assign your output to the OUT variable.
OUT = out

但我收到警告：“IronPythonEvaluator.EvaluateIronPythonScript 操作失败。 unindent 不匹配任何外部缩进级别”

Answer 1

不追加new list，而是用list1初始化new list，并在特定索引处替换new list中的值

list1 =["P324-12","P321-01","Pxxx-xx",[],"P134-23"]
list2 =["A00","A01","A02","A03","A04"]
out = list1
for i, itm in enumerate(out):
    if out[i] == [] or out[i] == "Pxxx-xx":
        out[i]=list2[i]
    

Answer 2

我尝试了以下方法，它似乎有效：

list1 =["P324-12","P321-01","Pxxx-xx",[],"P134-23"]
list2 =["A00","A01","A02","A03","A04"]
out = []

for idx, itm in enumerate(list1):
    if itm == [] or itm == "Pxxx-xx":
        out.append(list2[idx])
    else:
        out.append(itm)
#Assign your output to the OUT variable.
print(out)

那部分有什么用：

list1 = IN[0]
list2 = IN[1]