带有 IndexError 消息的并行列表

Question

我几乎完成了一个项目，如果没有“max = ring[0]”行的 IndexError，我似乎无法通过本节。如果有帮助，变量 ring 和 player 是常量变量，标记为 player = [] 和 ring = []。这是最新的 Python 3 版本。谢谢！

def main():
    player = []
    ring = []
    menu()
    addNBA(player, ring)
    rankNBA(player, ring)

# yes or no input request to continue updating ranking
def addNBA(player, ring):
    choice = "y"
    while choice.lower() != 'y' and choice.lower() != "n":
        print("Invalid. Enter 'y' or 'n'.")
        playerName = playerEntry()
        player.append(playerName)
        nbaRing = ringEntry()
        ring.append(nbaRing)
        choice = input("Do you want to continue updating the ranking? Enter 'y' or 'n'. ")

# sorts list of players and rings from lowest to highest amount of rings
def rankNBA(player, ring):
    max = ring[0]
    bestPlayer = player[0]
    min = ring[0]
    worsePlayer = player[0]
    print(player)
    for i in range(len(ring)):
        print(ring[i])
        if max < ring[i]:
            max = ring[i]
            bestPlayer = player[i]
        if min > ring[i]:
            min = ring[i]
            worsePlayer = player[i]

Answer 1

我认为您想要的是忽略错误并运行代码。 所以你应该使用 try except 语句： 根据您的代码尝试出现错误的地方：

def rankNBA(player, ring):
    try:
        max = ring[0]
    except IndexError:
        pass
    bestPlayer = player[0]
    min = ring[0]
    worsePlayer = player[0]
    print(player)
    for i in range(len(ring)):
        print(ring[i])
        if max < ring[i]:
            max = ring[i]
            bestPlayer = player[i]
        if min > ring[i]:
            min = ring[i]
            worsePlayer = player[i]

如果同样的错误再次出现在 min = ring[0] 或其他任何地方，请使用 try except。 结论

我们使用 try except 语句只是为了告诉程序它应该忽略错误并继续前进。

我希望这能回答你的问题。