【发布时间】:2020-08-10 16:19:36
【问题描述】:
我试图使用Joi.alternatives.try() 创建一个 Joi 模式。这是我尝试过的架构。
Joi.alternatives().try(Joi.object({
type: Joi.number().required().label('Error1!!')
}), Joi.object({
reason: Joi.string().required().label('Error2!!')
})).label('Error!!')
这是我用过的对象。
{ reason: 2 }
我期待错误为Error2!! 或包含此字符串Error2!! 的内容。但我收到错误
Validation Error: "Error!!" does not match any of the allowed types
此错误来自父节点。
如何使错误特定于对象?即,来自替代对象节点而不是父对象的错误。
您可以使用this平台在线验证架构。
更新: 这是我使用的示例架构。
employee_retired = Joi.object({
type: Joi.number().required().valid(2, 3, 7),
reason: Joi.string().required()
.min(1)
.max(100),
firstname: Joi.string()
.required(),
lastname: Joi.string()
.required()
.min(1)
.max(255),
personaldetails: Joi.alternatives().conditional('type', {
is: 2, then: Joi.array().items(Joi.object({
address: Joi.string().required()
.min(1)
.max(100),
salary: Joi.string().required()
.min(0)
.max(500),
contactnumbers: Joi.array().items(Joi.object({
mobile: Joi.string().required()
.min(0)
.max(15),
home: Joi.string()
.required()
.min(1)
.max(15),
})).max(50).required(),
}).required()).max(50).required(),
otherwise: Joi.forbidden(),
}),
monthlysavings: Joi.alternatives().conditional('type', {
is: 3,
then: Joi.number()
.required()
.min(0)
.max(50000),
otherwise: Joi.forbidden(),
}),
isapproved: Joi.boolean().required(),
});
empolyee_working = Joi.object({
type: Joi.number().required().valid(2, 3, 7),
reason: Joi.string().required()
.min(1)
.max(100),
firstname: Joi.string()
.required(),
lastname: Joi.string()
.required()
.min(1)
.max(255),
contactnumbers: Joi.array().items(Joi.object({
mobile: Joi.string().required()
.min(0)
.max(15),
home: Joi.string()
.required()
.min(1)
.max(15),
})).max(50).required(),
monthlysavings: Joi.alternatives().conditional('type', {
is: 3,
then: Joi.number().required()
.min(1)
.max(50000),
otherwise: Joi.forbidden(),
}),
isapproved: Joi.boolean().required(),
})
const employee = Joi.alternatives().try(employee_retired, empolyee_working);
【问题讨论】:
标签: javascript node.js hapijs joi