【发布时间】:2018-03-05 01:26:04
【问题描述】:
我正在开发一个 jQuery 分页工具,虽然我有分页工作,但我发现了一个缺陷:
拥有一排 14 个以上的分页链接在桌面上是可以的,但对于移动设备来说就不行了。所以我想一次将可见页面的数量限制为 5 个(不包括下一个/上一个按钮),并在它到达第三个可见页面时更新它并更新分页中的可见页面,基本上看起来像
| Prev | 1 | ... | 3 | 4 | 5 | 6 | Next |
我已经写了this CodePen 到目前为止的所有内容。我知道有插件可以为我执行此操作,但我想避免在此项目中使用插件。
HTML(分页的示例内容)
<div class="container" id="jar">
<div class="row content">
<div class="col">
<img src="http://via.placeholder.com/350x150">
</div>
<div class="col">
<img src="http://via.placeholder.com/350x150">
</div>
</div>
</div>
HTML(分页元素)
<nav>
<ul class="pagination justify-content-center pagination-sm">
<li id="previous-page" class="page-item"><a class="page-link" href="javascript:void(0)">Prev</a>
</li>
</ul>
</nav>
JavaScript:
"use strict";
//NOTE: the class"page-item page-link" are classes used in bootstrap 4 and will not be seen declared or used outside of the <li> as the bootstrap framework uses those classes to apply CSS
//sets number of items and limits the number of items per page
var numberOfItems = $("#jar .content").length;
var limitPerPage = 2;
//as the items start at 0 to keep the items per page at the limitPerPage set in variable, need to subtract 1 as is shown below
$("#jar .content:gt(" + (limitPerPage - 1) + ")").hide();
//sets total pages rounded to the next whole number
var totalPages = Math.round(numberOfItems / limitPerPage);
//append the 1 page to the pagination
$(".pagination").append(
"<li class='page-item current-page active'><a class='page-link' href='javascript:void(0)'>" +
1 +
"</a></li>"
);
//append the pages in sequential order after prev button (as seen in the html in codepen)
for (var i = 2; i <= totalPages; i++) {
$(".pagination").append(
"<li class='page-item current-page'><a class='page-link' href='javascript:void(0)'>" +
i +
"</a></li>"
);
}
//appends the next button link as the final child element in the pagination
$(".pagination").append(
"<li class='page-item' id='next-page'><a class='page-link' href='javascript:void(0)'>Next</a></li>"
);
//When a page is selected, if it has "active" class return false, if no "active" class, go to page and add "active" class attribute and remove from any other element that has "active" on it.
$(".pagination li.current-page").on("click", function () {
if ($(this).hasClass("active")) {
return false;
} else {
var currentPage = $(this).index();
$(".pagination li").removeClass("active");
$(this).addClass("active");
$("#jar .content").hide();
//.hide will hide content that does not fit into that page (ie 0 and 1 on page one, 2 and 3 on page two and so on will show on appropriate page) If it does not fall within the range for that page .hide, if it falls within the range .show content
var grandTotal = limitPerPage * currentPage;
for (var i = grandTotal - limitPerPage; i < grandTotal; i++) {
$("#jar .content:eq(" + i + ")").show();
}
}
});
//when next is clicked if it is on the last page, return false otherwise move on to next page in pagination and remove "active" class from previous page and add "active" class to new page
$("#next-page").on("click", function () {
var currentPage = $(".pagination li.active").index();
if (currentPage === totalPages) {
return false;
} else {
currentPage++;
$(".pagination li").removeClass("active");
$("#jar .content").hide();
var grandTotal = limitPerPage * currentPage;
for (var i = grandTotal - limitPerPage; i < grandTotal; i++) {
$("#jar .content:eq(" + i + ")").show();
}
$(".pagination li.current-page:eq(" + (currentPage - 1) + ")").addClass(
"active"
);
}
});
//when prev is clicked if it is on the 1 page, return false otherwise move on to previous page and remove "active" class from last page visited and add "active" class to new page
$("#previous-page").on("click", function () {
var currentPage = $(".pagination li.active").index();
if (currentPage === 1) {
return false;
} else {
currentPage--;
$(".pagination li").removeClass("active");
$("#jar .content").hide();
var grandTotal = limitPerPage * currentPage;
for (var i = grandTotal - limitPerPage; i < grandTotal; i++) {
$("#jar .content:eq(" + i + ")").show();
}
$(".pagination li.current-page:eq(" + (currentPage - 1) + ")").addClass(
"active"
);
}
});
【问题讨论】:
-
分享您的研究对每个人都有帮助。告诉我们您尝试了什么以及为什么它不能满足您的需求。这表明您已经花时间尝试帮助自己,它使我们免于重复明显的答案,最重要的是它可以帮助您获得更具体和相关的答案!另见:How to Ask
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我查看了不同插件的 js 文件,看看他们是如何做到的,大多数似乎破坏了分页并在达到某个页码阈值时重新绘制它。我不确定如何使用我编写的代码来复制它,因为我看过的插件并没有准确地解释他们对代码的每个部分做了什么。我查看了 YouTube 教程,在那里我找到了一个可以帮助编写此内容的教程,但没有找到一个可以帮助解释如何销毁和重绘分页的教程。
-
您应该考虑提供minimal reproducible example。我不想通读并尝试理解您发布的代码,因为老实说,它看起来很糟糕。
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格式化代码
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将 cmets 添加到 jquery 以及添加 html 示例(复制和粘贴以“row”类开头并保存在 id="jar" 的容器中,以便在测试时创建多个页面)。分页导航元素不需要在同一个容器中。如果您想查看实际代码以供参考,请使用this codepen
标签: jquery pagination