MYSQL / PHP 两个多选下拉过滤器（PDO）答案

【问题标题】：MYSQL / PHP TWO Multiselect Dropdown Filters (PDO)MYSQL / PHP 两个多选下拉过滤器（PDO）
【发布时间】：2017-11-07 02:32:36
【问题描述】：

我得到的错误如下：（我也在回显查询语句）

注意：第 75 行 /home/fanati10/public_html/wp-content/themes/digital-pro/page-nflwranalyzer.php 中的数组到字符串转换

注意：第 79 行 /home/fanati10/public_html/wp-content/themes/digital-pro/page-nflwranalyzer.php 中的数组到字符串转换
*SELECT * FROM WR_TeamAnalyzer WHERE TMID = ? AND WKID = ?*

这是我的 php 文件

  if(isset($_POST['submit']))
  {
      require_once( get_stylesheet_directory() . '/config/config.php' );
      if(isset($_POST['check'])) {
        $nflposs = "";
        foreach($_POST['check'] as $val => $text_field) {
          $nflposs.=$text_field.", ";
       }
          $nflpossint = rtrim($nflposs, ', ');
          $nflposs = explode(',', $nflpossint);
          $placeholders = rtrim(str_repeat('?, ', count($nflposs)), ', ');
          $filter[] = "TMID = $placeholders";
          $values[] = $nflpossint;
      }
       if(isset($_POST['wk'])) {
        $wkid = "";
        foreach($_POST['wk'] as $val => $text_field) {
          $wkid.=$text_field.", ";
       }
          $wkidint = rtrim($wkid, ', ');
          $wkid = explode(',', $wkidint);
          $placeholders2 = rtrim(str_repeat('?, ', count($wkid)), ', ');
          $filter[] = "WKID = $placeholders2";
          $values[] = $wkidint;
      }
      $sql="SELECT * FROM WR_TeamAnalyzer WHERE " . implode(' AND ', $filter);
      echo ($sql);
      $selectStmt = $dbcon->prepare($sql);
      $selectStmt->execute($values);
      $rows = $selectStmt->fetchAll();
  $tableContent = '';
  foreach ($rows as $row){
    $tableContent = $tableContent.'<tr>'.

【问题讨论】：

当我打印数组时，我得到 print_r($filter);数组 ( [0] => TMID = ? [1] => WKID = ?, ? ) print_r($values);数组 ( [0] => 3 [1] => 3, 4 )

标签： php mysql arrays pdo filtering

【解决方案1】：

当您在查询中使用= 时，它将需要一个字符串。但是您在参数中传递了一个数组 (values)。我不确定您要在这里实现什么，但如果您想签入一个数组，请在代码中更改这两行，如下所示：

TMID IN $placeholders
WKID IN $placeholders2

您的最终查询应如下所示：

SELECT * FROM WR_TeamAnalyzer WHERE TMID IN (?) AND WKID IN (?)

【讨论】：

您发布的内容仍然只允许按每列一个选项进行过滤......所以基本上根据您的回答，查询看起来像这样............ ...................... $sql="SELECT * FROM WR_TeamAnalyzer WHERE TMID IN (1) AND WKID IN (2)";
我想要的是过滤每个下拉列表中的多个选择的查询.....在这里我手动输入了我希望它如何过滤的查询...... ................................ $sql="SELECT * FROM WR_TeamAnalyzer WHERE TMID IN (1, 2) AND WKID IN ( 2, 3)";

【解决方案2】：

这是我想出来的

改变：

$filter[] = "TMID IN $placeholders";
$values = $nflpossint;

$filter[] = "WKID IN $placeholders2"; 
$values2 = $wkidint;

$sql="SELECT * FROM WR_TeamAnalyzer WHERE TMID IN ($values) AND WKID IN ($values2)";
$selectStmt = $dbcon->prepare($sql);
$selectStmt->execute();

【讨论】：

甚至不需要 $filter[](s)