使用角度的 RXJS 嵌套对象进行深度嵌套过滤的建议？

Question

快速提问：

对不起，我对 Typescipt 和 RxJS 还很陌生。我有以下 JSON：

[
{
    "ID": "",
    "UEN": "",
    "Name": "",
    "Address": "",
    "Telephone": "",
    "Fax": "",
    "Email": "",
    "Website": "",
    "Postal": "",
    "Status": ,
    "TimeCreated": ,
    "TimeUpdated": ,
    "Workheads": [{
            "ID": "",
            "Name": "",
            "Code": ""
        },
        {
            "ID": "",
            "Name": "",
            "Code": ""
        }
    ]
},
...
]

这个 json 通过 HTTP get() 的 Observable 输入到我的 Angular 应用程序中。

我如何过滤 workhead.Code 部分，以便我可以通过匹配内部 workhead.Code 来获得数组中的那些相关 Json 对象 strong> 到用户提供的特定字符串（例如 workhead.Code == 'CS2230'）？

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Answer 1

你并不清楚你想要返回什么。我假设您希望返回完整的对象，而不仅仅是内部的"Workheads"。您可以使用filter() 来获得您想要的：

const data = [{
  "ID": "",
  "UEN": "",
  "Name": "",
  "Address": "",
  "Telephone": "",
  "Fax": "",
  "Email": "",
  "Website": "",
  "Postal": "",
  "Status": "",
  "TimeCreated": "",
  "TimeUpdated": "",
  "Workheads": [{
    "ID": "",
    "Name": "",
    "Code": "abc"
  }, {
    "ID": "",
    "Name": "",
    "Code": "def"
  }]
}];

// Returns an array of the objects which contain matching code.
const getRelatedByCode = (arr, userProvidedCode) => {
  return arr.filter((i) => {
    return (i.Workheads || [])
      .some(wh => wh.Code === userProvidedCode);
  });
}

console.log(getRelatedByCode(data, 'abc')); // Returns array with the object
console.log(getRelatedByCode(data, 'zzz')); // Returns empty array