节点/Multer |无法根据字段名获取 sperarte 文件名

Question

我结合multer 创建了一个 Express 应用程序，用于在我的 Node.js 应用程序中上传项目

我尝试做的是选择让我们说：

Upload 1 - that has a fieldname of upfile1
Upload 2 - that has a fieldname of upfile2
Upload 3 - that has a fieldname of upfile3

基本上，我需要分别选择我的多上传应用程序的每个上传的文件名项。每次上传都需要在应用程序中针对不同的任务进行不同的处理。让我们以 console.log 为例，我需要做一些类似的事情：

console.log(req.body.upfile1.filename);
console.log(req.body.upfile2.filename);
console.log(req.body.upfile3.filename);

使用在我的视图中使用 name 属性定义的不同字段名来选择在应用程序中处理的不同项目。

下面是我的代码

查看 [index.html]

<form id="app-form" method="POST" class="fileupload" method="post" action="app" enctype="multipart/form-data">
<h1>Multi File Uploads</h1>
<input type="file" name="upfile1" value="">
<input type="file" name="upfile2" value="">
<input type="file" name="upfile3" value="">
<input type="submit" />
</form>

NodeJS [app.js]

app.get("/", function(req, res) {
  res.sendFile(__dirname + "/index.html");
});

app.post("/app", upload.any(), function(req, res) {
 let files = req.files;
 files.forEach(file => {
   console.log(file.filename);
});
 res.send(req.files);
 res.end();
});

非常感谢您的帮助，谢谢！

Answer 1

标记中的输入元素必须包含在表单中（它们可能已经包含在表单元素中，但未在您的问题中显示）。您还应该设置表单的enctype attribute to multipart/form-data。

<form method="post" enctype="multipart/form-data" action="/upload">
    <input type="file" name="upfile1">
    <input type="file" name="upfile2">
    <input type="file" name="upfile3">

    <input type="submit" value="Submit">
</form>

完成后，您可以配置 multer 并创建路由来处理文件上传：

const upload = multer({
  dest: path.join(__dirname, './upload') // You might want to change this according to your preferences
  // Since you're using any(), you might want to set fileFilter to control which files should be uploaded. See: https://github.com/expressjs/multer#filefilter
});

const findFileByFieldname = (files, fieldname) => {
  return files.find(file => file.fieldname === fieldname) || {};
}

app.post("/upload", upload.any(), (req, res) => {     
  const upfile1Filename = findFileByFieldname(req.files, 'upfile1').filename;
  const upfile2Filename = findFileByFieldname(req.files, 'upfile2').filename;
  const upfile3Filename = findFileByFieldname(req.files, 'upfile3').filename;

  res.json({
    upfile1Filename,
    upfile2Filename,
    upfile3Filename,
  });
});

// Example response (Node v8.11.4, Express v4.16.3, Multer v1.3.1)
// {"upfile1Filename":"360726b532a01b0e31832f067b5922c8","upfile2Filename":"144e1298437afb51f36eb37c77814650","upfile3Filename":"4c908da20e770130377e4006db945af6"}