【发布时间】:2018-02-22 16:11:51
【问题描述】:
我的目标是使用 neo4j 对文档进行两种不同的搜索。我将使用食谱(文档)作为我的示例。 假设我手头有一份配料(关键词)列表(牛奶、黄油、面粉、盐、糖、鸡蛋……),我的数据库中有一些食谱,每个食谱都附有配料。我想输入我的列表并得到两个不同的结果。一个是最接近包含我输入的所有成分的食谱。第二种是包含我所有成分的食谱组合。
给定:牛奶、黄油、面粉、盐、糖、鸡蛋
第一种情况的搜索结果可能是:
1.)糖饼干
2.)黄油曲奇
第二个结果可能是:
1.)扁面包和 Gogel-Mogel
我正在阅读要插入 neo4j 的食谱,然后从每个食谱顶部的成分列表中提取成分,然后从食谱说明中提取成分。我想以不同的方式称重,可能是 60/40 以支持成分列表。
我还想把每种成分都删掉,以防人们输入相似的词。
我正在努力在 neo4j 中提出一个好的数据模型。我计划让用户输入英文成分,我会在后台停止它们,并使用它进行搜索。
我的第一个想法是: 这对我来说很直观,但要找到所有食谱需要很多时间。
接下来可能是这样的:
直接从茎中获取食谱,但我需要在关系中传递食谱 ID(对吗?)以获取实际成分。
第三,也许像这样组合它们? 但是有很多重复。
这里还有一些 CYPHER 语句来创建第一个想法:
//Create 4 recipes
create (r1:Recipe {rid:'1', title:'Sugar cookies'}), (r2:Recipe {rid:'2', title:'Butter cookies'}),
(r3:Recipe {rid:'3', title:'Flat bread'}), (r4:Recipe {rid:'4', title:'Gogel-Mogel'})
//Adding some ingredients
merge (i1:Ingredient {ingredient:"salted butter"})
merge (i2:Ingredient {ingredient:"white sugar"})
merge (i3:Ingredient {ingredient:"brown sugar"})
merge (i4:Ingredient {ingredient:"all purpose flour"})
merge (i5:Ingredient {ingredient:"iodized salt"})
merge (i6:Ingredient {ingredient:"eggs"})
merge (i7:Ingredient {ingredient:"milk"})
merge (i8:Ingredient {ingredient:"powdered sugar"})
merge (i9:Ingredient {ingredient:"wheat flour"})
merge (i10:Ingredient {ingredient:"bananas"})
merge (i11:Ingredient {ingredient:"chocolate chips"})
merge (i12:Ingredient {ingredient:"raisins"})
merge (i13:Ingredient {ingredient:"unsalted butter"})
merge (i14:Ingredient {ingredient:"wheat flour"})
merge (i15:Ingredient {ingredient:"himalayan salt"})
merge (i16:Ingredient {ingredient:"chocolate bars"})
merge (i17:Ingredient {ingredient:"vanilla flavoring"})
merge (i18:Ingredient {ingredient:"vanilla"})
//Stems added to each ingredient
merge (i1)<-[:STEM_OF]-(s1:Stem {stem:"butter"})
merge (i2)<-[:STEM_OF]-(s2:Stem {stem:"sugar"})
merge (i3)<-[:STEM_OF]-(s2)
merge (i4)<-[:STEM_OF]-(s4:Stem {stem:"flour"})
merge (i5)<-[:STEM_OF]-(s5:Stem {stem:"salt"})
merge (i6)<-[:STEM_OF]-(s6:Stem {stem:"egg"})
merge (i7)<-[:STEM_OF]-(s7:Stem {stem:"milk"})
merge (i8)<-[:STEM_OF]-(s2)
merge (i9)<-[:STEM_OF]-(s4)
merge (i10)<-[:STEM_OF]-(s10:Stem {stem:"banana"})
merge (i11)<-[:STEM_OF]-(s11:Stem {stem:"chocolate"})
merge (i12)<-[:STEM_OF]-(s12:Stem {stem:"raisin"})
merge (i13)<-[:STEM_OF]-(s1)
merge (i14)<-[:STEM_OF]-(s4)
merge (i15)<-[:STEM_OF]-(s5)
merge (i16)<-[:STEM_OF]-(s11)
merge (i17)<-[:STEM_OF]-(s13:Stem {stem:"vanilla"})
merge (i18)<-[:STEM_OF]-(s13)
create (r1)<-[:INGREDIENTS_LIST{weight:.7}]-(i1)
create (r1)<-[:INGREDIENTS_LIST{weight:.6}]-(i2)
create (r1)<-[:INGREDIENTS_LIST{weight:.5}]-(i4)
create (r1)<-[:INGREDIENTS_LIST{weight:.4}]-(i5)
create (r1)<-[:INGREDIENTS_LIST{weight:.4}]-(i6)
create (r1)<-[:INGREDIENTS_LIST{weight:.2}]-(i7)
create (r1)<-[:INGREDIENTS_LIST{weight:.1}]-(i18)
create (r2)<-[:INGREDIENTS_LIST{weight:.7}]-(i1)
create (r2)<-[:INGREDIENTS_LIST{weight:.6}]-(i3)
create (r2)<-[:INGREDIENTS_LIST{weight:.5}]-(i4)
create (r2)<-[:INGREDIENTS_LIST{weight:.4}]-(i5)
create (r2)<-[:INGREDIENTS_LIST{weight:.3}]-(i6)
create (r2)<-[:INGREDIENTS_LIST{weight:.2}]-(i7)
create (r2)<-[:INGREDIENTS_LIST{weight:.1}]-(i18)
create (r3)<-[:INGREDIENTS_LIST{weight:.7}]-(i1)
create (r3)<-[:INGREDIENTS_LIST{weight:.6}]-(i5)
create (r3)<-[:INGREDIENTS_LIST{weight:.5}]-(i7)
create (r3)<-[:INGREDIENTS_LIST{weight:.4}]-(i9)
create (r4)<-[:INGREDIENTS_LIST{weight:.6}]-(i2)
create (r4)<-[:INGREDIENTS_LIST{weight:.5}]-(i6)
create (r1)<-[:INGREDIENTS_INSTR{weight:.2}]-(i1)
create (r1)<-[:INGREDIENTS_INSTR{weight:.2}]-(i2)
create (r1)<-[:INGREDIENTS_INSTR{weight:.2}]-(i4)
create (r1)<-[:INGREDIENTS_INSTR{weight:.2}]-(i5)
create (r1)<-[:INGREDIENTS_INSTR{weight:.1}]-(i6)
create (r1)<-[:INGREDIENTS_INSTR{weight:.1}]-(i7)
create (r2)<-[:INGREDIENTS_INSTR{weight:.3}]-(i1)
create (r2)<-[:INGREDIENTS_INSTR{weight:.2}]-(i3)
create (r2)<-[:INGREDIENTS_INSTR{weight:.2}]-(i4)
create (r2)<-[:INGREDIENTS_INSTR{weight:.2}]-(i5)
create (r2)<-[:INGREDIENTS_INSTR{weight:.2}]-(i6)
create (r2)<-[:INGREDIENTS_INSTR{weight:.1}]-(i7)
create (r3)<-[:INGREDIENTS_INSTR{weight:.3}]-(i1)
create (r3)<-[:INGREDIENTS_INSTR{weight:.3}]-(i5)
create (r3)<-[:INGREDIENTS_INSTR{weight:.1}]-(i7)
create (r3)<-[:INGREDIENTS_INSTR{weight:.1}]-(i9)
create (r4)<-[:INGREDIENTS_INSTR{weight:.3}]-(i2)
create (r4)<-[:INGREDIENTS_INSTR{weight:.3}]-(i6)
以及带有上述语句的 neo4j 控制台的链接: http://console.neo4j.org/?id=3o8y44
neo4j 有多关心多重关系?另外,我可以做一种单一的成分,但是我如何组合一个查询来获取给定一种以上成分的食谱?
编辑: 谢谢迈克尔!这让我更进一步。我能够扩展您对此的回答:
WITH split("egg, sugar, chocolate, milk, flour, salt",", ") as terms UNWIND
terms as term MATCH (stem:Stem {stem:term})-[:STEM_OF]->
(ingredient:Ingredient)-[lst:INGREDIENTS_LIST]->(r:Recipe) WITH r,
size(terms) - count(distinct stem) as notCovered, sum(lst.weight) as weight,
collect(distinct stem.stem) as matched RETURN r , notCovered,matched, weight
ORDER BY notCovered ASC, weight DESC
并获得了匹配的成分列表和重量。如何更改查询以显示 :INGREDIENTS_INSTR 关系的权重,以便我可以同时使用两个权重进行计算? [lst:INGREDIENTS_LIST|INGREDIENTS_INSTR] 不是我想要的。
编辑:
这似乎有效,对吗?
WITH split("egg, sugar, chocolate, milk, flour, salt",", ") as terms UNWIND
terms as term MATCH (stem:Stem {stem:term})-[:STEM_OF]->
(ingredient:Ingredient)-[lstl:INGREDIENTS_LIST]->(r:Recipe)<-
[lsti:INGREDIENTS_INSTR]-(ingredient:Ingredient) WITH r, size(terms) -
count(distinct stem) as notCovered, sum(lsti.weight) as wi, sum(lstl.weight)
as wl, collect(distinct stem.stem) as matched RETURN r ,
notCovered,matched, wl+wi ORDER BY notCovered ASC, wl+wi DESC
另外,您能帮忙解答第二个问题吗?在给定成分列表的情况下,将返回包含给定成分的食谱组合。再次感谢!
【问题讨论】:
标签: neo4j data-modeling keyword-search