【问题标题】:How to get Avro data from Confluent Schema Registry in String format from kafka in pyspark?如何从 pyspark 中的 kafka 以字符串格式从 Confluent Schema Registry 获取 Avro 数据?
【发布时间】:2020-04-17 04:48:49
【问题描述】:

我正在从 Spark(结构化流)中的 Kafka 中读取数据,但是从 Spark 中的 kafka 获取的数据不是字符串格式。 火花:2.3.4

Kafka 数据格式:

{"Patient_ID":316,"Name":"Richa","MobileNo":{"long":7049123177},"BDate":{"int":740},"Gender":"female"}

这是 kafka 触发结构化流的代码:

#  spark-submit --jars kafka-clients-0.10.0.1.jar --packages org.apache.spark:spark-avro_2.11:2.4.0,org.apache.spark:spark-sql-kafka-0-10_2.11:2.3.0,org.apache.spark:spark-streaming-kafka-0-8-assembly_2.11:2.3.4,org.apache.spark:spark-streaming-kafka-0-8_2.11:2.2.0 /home/kinjalpatel/kafka_sppark.py
import pyspark
from pyspark import SparkContext
from pyspark.sql.session import SparkSession
from pyspark.sql.types import *
from pyspark.sql.functions import *
import json
from pyspark.sql.functions import from_json, col, struct
from pyspark.sql.types import StructField, StructType, StringType, DoubleType
from confluent_kafka.avro.serializer.message_serializer import MessageSerializer
from confluent_kafka.avro.cached_schema_registry_client import CachedSchemaRegistryClient
from pyspark.sql.column import Column, _to_java_column

sc = SparkContext()
sc.setLogLevel("ERROR")
spark = SparkSession(sc)
schema_registry_client = CachedSchemaRegistryClient(
url='http://localhost:8081')
serializer = MessageSerializer(schema_registry_client)
df = spark.readStream.format("kafka") \
  .option("kafka.bootstrap.servers", "localhost:9092") \
  .option("subscribe", "mysql-01-Patient") \
  .option("partition.assignment.strategy", "range") \
  .option("valueConverter", "org.apache.spark.examples.pythonconverters.AvroWrapperToJavaConverter") \
  .load()
df.printSchema()
mta_stream=df.selectExpr("CAST(key AS STRING)", "CAST(value AS STRING)", "CAST(topic AS STRING)", "CAST(partition AS STRING)", "CAST(offset AS STRING)", "CAST(timestamp AS STRING)", "CAST(timestampType AS STRING)")
mta_stream.printSchema()
qry = mta_stream.writeStream.outputMode("append").format("console").start()
qry.awaitTermination()

这是我得到的输出:

+----+--------------------+----------------+---------+------+--------------------+-------------+
| key|               value|           topic|partition|offset|           timestamp|timestampType|
+----+--------------------+----------------+---------+------+--------------------+-------------+
|null|�
Richa���...|mysql-01-Patient|        0|   160|2019-12-27 11:56:...|            0|
+----+--------------------+----------------+---------+------+--------------------+-------------+

如何获取字符串格式的value列?

【问题讨论】:

  • 您显然得到了一些东西,尽管使用格式很难看出是什么。您能否更具体地说明哪一部分看起来与预期不同(您所看到的与您所期望的)?
  • 你在使用 Confluent Schema Registry 吗?记录是 avro 编码的(有或没有 Confluent Schema Registry)吗?
  • 是的,数据是 avro 编码的@JacekLaskowski
  • 需要以可读格式从kafka中获取数据@DennisJaheruddin
  • 您需要deserialize value 字段才能看到消息。可以使用confluent的KafkaAvroDeserializer

标签: apache-spark apache-kafka avro spark-structured-streaming confluent-schema-registry


【解决方案1】:

来自Spark documentation

import org.apache.spark.sql.avro._

// `from_avro` requires Avro schema in JSON string format.
val jsonFormatSchema = new String(Files.readAllBytes(Paths.get("./examples/src/main/resources/user.avsc"    )))

val df = spark
    .readStream
  .format("kafka")
  .option("kafka.bootstrap.servers", "host1:port1,host2:port2")
  .option("subscribe", "topic1")
  .load()


val output = df
  .select(from_avro('value, jsonFormatSchema) as 'user)
  .where("user.favorite_color == \"red\"")
  .select(to_avro($"user.name") as 'value)

val query = output
  .writeStream
  .format("kafka")
  .option("kafka.bootstrap.servers", "host1:port1,host2:port2")
  .option("topic", "topic2")
  .start()

来自databricks documentation

import org.apache.spark.sql.avro._
import org.apache.avro.SchemaBuilder

// When reading the key and value of a Kafka topic, decode the
// binary (Avro) data into structured data.
// The schema of the resulting DataFrame is: <key: string, value: int>
val df = spark
  .readStream
  .format("kafka")
  .option("kafka.bootstrap.servers", servers)
  .option("subscribe", "t")
  .load()
  .select(
    from_avro($"key", SchemaBuilder.builder().stringType()).as("key"),
    from_avro($"value", SchemaBuilder.builder().intType()).as("value"))

【讨论】:

  • 这仅适用于 Databricks 平台,而非任何 Spark 消费者
  • 是的,我是。您可以在 spark-avro github 页面上找到同样多的问题。此外,从 Spark 2.4 开始的 spark-avro 不支持 Confluent Schema Registry,因此我建议您在从文档中复制之前尝试您的答案
【解决方案2】:

对于从 Kafka 主题读取 Avro 消息并在 pyspark 结构化流中解析,没有相同的直接库。但是我们可以通过编写小型包装器来读取/解析 Avro 消息,并在您的 pyspark 流代码中将该函数称为 UDF。

请参考:

Reading avro messages from Kafka in spark streaming/structured streaming

【讨论】:

  • 使用 Schema Registry 的答案在哪里?
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